互联网上的公平人士!
如果我愿意,可以快速提问董事会的亲切天才......
我正在尝试'过滤'(因为缺少一个更好的术语)会产生数据集,而这实际上是我们拥有该组的ID然后是集体ID的情况。可能更容易说“租户参考”和“租赁参考”,因为这就是我正在使用的!
我已经能够得到我所追求的东西,虽然无疑是一种无礼的方式,而且......不是我需要的,因为有重复。
由于我正在使用的数据充满机密性,我无法发布任何数据,但这是我的查询:
SELECT DISTINCT
Pr.Ref AS PPROPERTYID,
Ty.GlobalReference AS PPREVREF,
Ty.Tenancy_Id AS TenancyId,
Tt1.Tenant_Id AS TenantId,
Tt1.Title AS Title,
Tt1.Forename + ' ' +
CASE
WHEN Tt1.Middlename IS NULL
THEN ''
ELSE Tt1.Middlename
END AS FirstName,
Tt1.Surname AS Surname,
Tt1.LandPhone AS HomePhone,
Tt1.Mobile AS Mobile,
Tt1.EMail AS Email,
Tt2.Title AS Title2,
Tt2.Forename + ' ' +
CASE
WHEN Tt2.Middlename IS NULL
THEN ''
ELSE Tt2.Middlename
END AS FirstName2,
Tt2.Surname AS Surname2,
Tt3.Title AS Title3,
Tt3.Forename + ' ' +
CASE
WHEN Tt3.Middlename IS NULL
THEN ''
ELSE Tt3.Middlename
END AS FirstName3,
Tt3.Surname AS Surname3,
Tt4.Title AS Title4,
Tt4.Forename + ' ' +
CASE
WHEN Tt4.Middlename IS NULL
THEN ''
ELSE Tt4.Middlename
END AS FirstName4,
Tt4.Surname AS Surname4,
Tt5.Title AS Title5,
Tt5.Forename + ' ' +
CASE
WHEN Tt5.Middlename IS NULL
THEN ''
ELSE Tt5.Middlename
END AS FirstName5,
Tt5.Surname AS Surname5,
Tt6.Title AS Title6,
Tt6.Forename + ' ' +
CASE
WHEN Tt6.Middlename IS NULL
THEN ''
ELSE Tt6.Middlename
END AS FirstName6,
Tt6.Surname AS Surname6,
'END1234' AS 'END1234'
FROM Tenancy Ty
LEFT JOIN Tenancies Tys ON Ty.Tenancies_Id = Tys.Tenancies_Id
LEFT JOIN Property Pr ON Tys.Property_Id = Pr.Property_Id
LEFT JOIN Landlords LLs ON Pr.Property_Id = LLs.Property_Id
LEFT JOIN LandlordJoin LLJ ON LLs.Landlords_Id = LLJ.Landlords_Id1
LEFT JOIN Tenants Tts ON Ty.Tenancy_Id = Tts.Tenancy_Id
LEFT JOIN Tenant Tt ON Tts.Tenants_Id = Tt.Tenants_Id
LEFT JOIN Conditions Con ON Ty.Tenancy_Id = Con.Tenancy_Id
LEFT JOIN Tenant Tt1 ON Tts.Tenants_Id = Tt1.Tenants_Id
LEFT JOIN Tenant Tt2 ON Tts.Tenants_Id = Tt2.Tenants_Id AND Tt2.Tenant_Id <> Tt1.Tenant_Id
LEFT JOIN Tenant Tt3 ON Tts.Tenants_Id = Tt3.Tenants_Id AND Tt3.Tenant_Id <> Tt2.Tenant_Id AND Tt3.Tenant_Id <> Tt1.Tenant_Id
LEFT JOIN Tenant Tt4 ON Tts.Tenants_Id = Tt4.Tenants_Id AND Tt4.Tenant_Id <> Tt3.Tenant_Id AND Tt4.Tenant_Id <> Tt2.Tenant_Id
AND Tt4.Tenant_Id <> Tt1.Tenant_Id
LEFT JOIN Tenant Tt5 ON Tts.Tenants_Id = Tt5.Tenants_Id AND Tt5.Tenant_Id <> Tt4.Tenant_Id AND Tt5.Tenant_Id <> Tt3.Tenant_Id
AND Tt5.Tenant_Id <> Tt2.Tenant_Id AND Tt5.Tenant_Id <> Tt1.Tenant_Id
LEFT JOIN Tenant Tt6 ON Tts.Tenants_Id = Tt6.Tenants_Id AND Tt6.Tenant_Id <> Tt5.Tenant_Id AND Tt6.Tenant_Id <> Tt4.Tenant_Id
AND Tt6.Tenant_Id <> Tt3.Tenant_Id AND Tt6.Tenant_Id <> Tt2.Tenant_Id
AND Tt6.Tenant_Id <> Tt1.Tenant_Id
请记住,这是一个“工作副本”,所以为加入大灾难的丑陋和纯粹的混乱道歉!
有没有人知道为什么结果可能会转换价值(多个Tenant_Id链接到一个Tenancy_Id)?查询似乎确实返回了正确数量的租户,但是正在复制行...而我希望有一个漂亮,整洁的单行,其中租户值整齐地显示在相应的列中。
提前谢谢大家 - 如果由于摄入咖啡因导致的咖啡因摄入量过高而导致过度摄入量过低而道歉,并且与单个人的摄取量相比更为一致!
罗布