Question

我有一个数组：

issues={#<Issue id: 669, tracker_id: 2,parent_id: 663,
 #<Issue id: 668, tracker_id: 2, parent_id: 663,
 #<Issue id: 667, tracker_id: 2, parent_id: 665,
 #<Issue id: 666, tracker_id: 2, parent_id: 665,
 #<Issue id: 665, tracker_id: 2, parent_id: 658,
 #<Issue id: 664, tracker_id: 2, parent_id: 662,
 #<Issue id: 663, tracker_id: 2, parent_id: 662,
 #<Issue id: 662, tracker_id: 2, parent_id: 658,
 #<Issue id: 661, tracker_id: 2, parent_id: nil}]

如果我使用group_by：

 leveled_tasks = issues.sort_by(&:id).group_by(&:parent)

我得到以下结果：

{ nil=>[#<Issue id: 661, tracker_id: 2, parent_id: nil}],
 658=>[#<Issue id: 665, tracker_id: 2, parent_id: 658,
 #<Issue id: 662, tracker_id: 2, parent_id: 658],
 662=>[#<Issue id: 664, tracker_id: 2, parent_id: 662,
 #<Issue id: 663, tracker_id: 2, parent_id: 662],
 663=>[#<Issue id: 669, tracker_id: 2,parent_id: 663,
 #<Issue id: 668, tracker_id: 2, parent_id: 663],
 665=>[#<Issue id: 667, tracker_id: 2, parent_id: 665,
 #<Issue id: 666, tracker_id: 2, parent_id: 665]}

我想要它：

{ 0=>[#<Issue id: 661, tracker_id: 2, parent_id: nil}],
 1=>[#<Issue id: 665, tracker_id: 2, parent_id: 658,
 #<Issue id: 662, tracker_id: 2, parent_id: 658],
 2=>[#<Issue id: 664, tracker_id: 2, parent_id: 662,
 #<Issue id: 663, tracker_id: 2, parent_id: 662],
 3=>[#<Issue id: 669, tracker_id: 2,parent_id: 663,
 #<Issue id: 668, tracker_id: 2, parent_id: 663],
 4=>[#<Issue id: 667, tracker_id: 2, parent_id: 665,
 #<Issue id: 666, tracker_id: 2, parent_id: 665]}

我使用group_by level，但它给了我：

 NoMethodError (undefined method level' for #<Issue:0xb514796c>): lib/redmine/sudo_mode.rb:63:in sudo_mode'

为此：

leveled_tasks = issues.sort_by(&:id).group_by(&:level)

Answer 1

您可以循环哈希键并开始填充一个具有所需输出的新键，如：

grouped_issues = issues.sort_by(&:id).group_by(&:parent)
leveled_tasks = {}
grouped_issues.keys.each_with_index do |key, index| 
  leveled_tasks[index] = grouped_issues[key]
end

在group_by结果后更改密钥

1 个答案: