在这里,我需要清楚地解释我的问题。如何使用mongoose和nodejs编写查询以检索与条件匹配的每个子文档数组。
这是我现有的JSON:
[
{
_id: "568ccd6e646489f4106470ec",
area_name: "Padi",
warehouse_name: "Hapserve Online Water Service",
name: "Ganesh",
email: "ganesh@excrin.com",
mobile_no: "9042391491",
otp: "4466",
__v: 0,
date: "06-01-2016",
booking:
[
{
can_quantity: "4",
delivery_date: "06-01-2016",
delivery_timeslot: "10am-3pm",
subscription: "true",
subscription_type: "Weekly",
total_cost: "240",
order_id: "S13833",
can_name: "Tata Waters",
address: "15/A,Ramanrajan street,,Padi,Chennai",
can_cost: "240",
_id: "568ccd6e646489f4106470ee",
ordered_at: "2016-01-06T08:16:46.825Z",
status: "UnderProcess"
},
{
can_name: "Bisleri",
can_quantity: "4",
can_cost: "200",
delivery_date: "11-01-2016",
delivery_timeslot: "3pm-8pm",
order_id: "11537",
address: "27,Main Street,Padi,Chennai",
_id: "5693860edb988e241102d196",
ordered_at: "2016-01-11T10:38:06.749Z",
status: "UnderProcess"
}
]
},
{
_id: "56937fb8920629a0164604d8",
area_name: "Poonamallee",
warehouse_name: "Tata Waters",
name: "M.Kalaiselvan",
email: "kalai131192@gmail.com",
mobile_no: "9003321521",
otp: "2256",
__v: 0,
date: "2016-01-11T10:11:04.266Z",
booking:
[
{
can_quantity: "4",
delivery_date: "06-01-2016",
delivery_timeslot: "10am-3pm",
subscription: "true",
subscription_type: "Alternate",
total_cost: "640",
order_id: "S13406",
can_name: "Kinley",
address: "133,Bajanai koil street, Melmanagar,Poonamallee,Chennai",
can_cost: "160",
_id: "56937fb8920629a0164604da",
ordered_at: "11-01-2016",
status: "UnderProcess"
},
{
can_name: "Tata Waters",
can_quantity: "2",
can_cost: "120",
delivery_date: "11-01-2016",
delivery_timeslot: "10am-3pm",
order_id: "11387",
address: "140,Bajanai koil street, Melmanagar,Poonamallee,Chennai",
_id: "56937ff7920629a0164604dc",
ordered_at: "2016-01-11T10:12:07.719Z",
status: "UnderProcess"
},
{
can_name: "Bisleri",
can_quantity: "4",
can_cost: "200",
delivery_date: "12-01-2016",
delivery_timeslot: "10am-3pm",
order_id: "16853",
address: "140,Bajanai koil street, Melmanagar,Poonamallee,Chennai",
_id: "56938584db988e241102d194",
ordered_at: "2016-01-11T10:35:48.911Z",
status: "UnderProcess"
},
{
can_name: "Hapserve",
can_quantity: "6",
can_cost: "150",
delivery_date: "11-01-2016",
delivery_timeslot: "10am-3pm",
order_id: "17397",
address: "133,Bajanai koil street, Melmanagar,Poonamallee,Chennai",
_id: "569385bbdb988e241102d195",
ordered_at: "2016-01-11T10:36:43.918Z",
status: "UnderProcess"
},
{
can_name: "Bisleri",
can_quantity: "5",
can_cost: "250",
delivery_date: "11-01-2016",
delivery_timeslot: "10am-3pm",
order_id: "14218",
address: "133,Bajanai koil street, Melmanagar,Poonamallee,Chennai",
_id: "56939a13c898ef7c0cc882b0",
ordered_at: "2016-01-11T12:03:31.324Z",
status: "Cancelled"
}
]
}
]
在这里,我需要检索交货日期为今天的每个文件
所以这是我的nodejs route
router.get('/booking-date/:date', function(req, res){
var id = req.params.date;
RegisterList.find({'booking.delivery_date':id}, {'booking.$':1}, function(err, docs){
if(err)
throw err;
res.json(docs);
});
});
虽然使用此功能但无法获取所有数据。只从集合中检索两个数据。
示例如果我搜索日期11-01-2016 am只获取一个子文档 每个父ID,但在上面的json中为日期11-01-2016。对于一个父ID,该日期有2个子文档,另一个父ID具有该日期的1个子文档。
我无法将mongoose查询检索写入匹配完成的每个子文档。 帮助将不胜感激......
答案 0 :(得分:1)
听起来您可能想尝试 aggregation framework ,您可以 $project
预订数组,并使用 $setDifference
, $map
和 $cond
运营商。
$map
运算符检查booking
数组中的每个元素, $cond
运算符仅返回基于的所需字段如果是真正的条件,则返回错误的值而不是数组元素。 $setDifference
运算符然后通过与具有[false]值的另一个集合进行比较来删除数组中的所有false值,最终结果只是返回的匹配项:
router.get('/booking-date/:date', function(req, res){
var id = req.params.date,
pipeline = [
{
"$match": { 'booking.delivery_date': id }
},
{
"$project": {
"booking": {
"$setDifference": [
{
"$map": {
"input": "$booking",
"as": "el",
"in": {
"$cond": [
{ "$eq": [ "$$el.delivery_date", id ] },
"$$el",
false
]
}
}
},
[false]
]
}
}
}
];
RegisterList.aggregate(pipeline, function(err, docs){
if(err) throw err;
res.json(docs);
});
});
答案 1 :(得分:0)
$ projection运算符只投影第一个匹配元素,请参考here
项目所有子文档{bookings:1},然后过滤应用程序中的子文档。