Question

$qry="SELECT * 
      FROM `tbl_postad` 
      WHERE category LIKE '% $car %'
        OR title LIKE '% $car %' 
        OR text LIKE '% $car %'";

编辑：抱歉错过了$。语法错误 - 好的

 id category title description   
  1    car 
  2    car
  3            car
  4            car
  5            car
  6                    car


?>

但我希望输出首先按类别列出行，然后是标题，然后是描述。有没有使用工会提前致谢。

示例：

prePersist

Answer 1

ORDER BY CASE WHEN category LIKE '% $car %' THEN 0
              WHEN title LIKE '% $car %' THEN 1
              WHEN description LIKE '% $car %' THEN 2
         END

Answer 2

您可以尝试如下：

SELECT * 
FROM `tbl_postad` 
WHERE category LIKE '%car%' OR title LIKE '%car%' OR description LIKE '%car%'
ORDER BY (category LIKE '%car%') DESC,
     (title LIKE '%car%') DESC,
     (description LIKE '%car%') DESC;

Answer 3

您可以使用like as =`：

进行同样的思考

SELECT * 
FROM `tbl_postad` 
WHERE category LIKE '% car %' OR title LIKE '% car %' OR text LIKE '% car %'
ORDER BY (category LIKE '% car %') DESC,
         (title LIKE '% car %') DESC,
         (text LIKE '% car %') DESC;

根据您的示例数据，我假设您打算OR而不是AND。

mysql：选择使用like运算符并按列名对结果进行排序

3 个答案: