问题
我们有一个Users表和一个Addresses表。每个用户可以拥有多个地址。我们有一个名为 IsDefault
的字段,用户可以在其中选择默认地址。该字段目前不是强制性的,可能将来也是如此,因此我需要做一些分析。现在我想验证地址以查看:
基本上我想知道有多少用户有多个地址没有打开他们的任何地址作为默认地址。
到目前为止,我有以下SQL查询:
SELECT AD.User_Id,
COUNT(AD.User_Id) AS HowManyAddresses,
SUM(
CASE WHEN
AD.IsDefault IS NULL
OR
AD.IsDefault = 0
THEN
1
ELSE
0
END
) AS DefaultEmpty,
SUM(
CASE WHEN
AD.IsDefault = 1
THEN
1
ELSE
0
END
) AS DefaultAddress
FROM dbo.Addresses AS AD
JOIN dbo.Users AS U
ON U.Id = AD.User_Id
GROUP BY AD.User_ID
ORDER BY AD.User_Id
我发现的问题是我想检查DefaultAddress
和DefaultEmpty
SELECT SUM字段中的值,但是在尝试使用WHERE或HAVING引用它们时出现以下错误:
无效的列名'DefaultEmpty'。
是否无法引用SUM值以供选择?
技术使用:
答案 0 :(得分:1)
实际上你需要用这样的SUM
重复整个HAVING
条款 -
SELECT
AD.User_Id
,COUNT(AD.User_Id) AS HowManyAddresses
,SUM(
CASE
WHEN
AD.IsDefault IS NULL OR
AD.IsDefault = 0 THEN 1
ELSE 0
END
) AS DefaultEmpty
,SUM(
CASE
WHEN
AD.IsDefault = 1 THEN 1
ELSE 0
END
) AS DefaultAddress
FROM dbo.Addresses AS AD
JOIN dbo.Users AS U
ON U.Id = AD.User_Id
GROUP BY AD.User_ID
HAVING SUM(
CASE
WHEN
AD.IsDefault IS NULL OR
AD.IsDefault = 0 THEN 1
ELSE 0
END
) = 0
ORDER BY AD.User_Id
OR
DECLARE @address TABLE(UserID INT,Address VARCHAR(100),IsDefault BIT);
INSERT INTO @address VALUES
(1,'User 1 default',1)
,(2,'User 2 non default',0)
,(3,'User 3 non default',0)
,(3,'User 3 default',1)
,(4,'User 4 default',1)
,(4,'User 4 second default',1);
SELECT
COUNT(*) OVER () AS HowManyAddresses
,ISNULL(def0.DefaultEmpty, 0) AS DefaultEmpty
,ISNULL(def1.DefaultAddress, 0) AS DefaultAddress
FROM (SELECT
AD.Address
,COUNT(AD.UserID) OVER (PARTITION BY AD.UserID) AS DefaultEmpty
FROM @address AS AD
WHERE (AD.IsDefault = 0)) def0
FULL JOIN (SELECT
AD.Address
,COUNT(AD.UserID) OVER (PARTITION BY AD.UserID) AS DefaultAddress
FROM @address AS AD
WHERE (AD.IsDefault = 1)) def1
ON def0.Address = def1.Address
答案 1 :(得分:1)
这将计算 - 按用户和默认分组,有多少个地址:
DECLARE @user TABLE(ID INT, Name VARCHAR(100));
INSERT INTO @user VALUES
(1,'user1') --will get a default
,(2,'user2') --no default
,(3,'user3') --both
,(4,'user4') --two defaults
,(5,'user5');--nothing
DECLARE @address TABLE(UserID INT,Address VARCHAR(100),IsDefault BIT);
INSERT INTO @address VALUES
(1,'User 1 default',1)
,(2,'User 2 non default',0)
,(3,'User 3 non default',0)
,(3,'User 3 default',1)
,(4,'User 4 default',1)
,(4,'User 4 second default',1);
编辑:PIVOT更好......
SELECT p.*
FROM
(
SELECT u.ID,u.Name
,CASE WHEN a.IsDefault=1 THEN 'DEFAULT' ELSE 'NORMAL' END AS PivotColumn
,COUNT(a.UserID) AS CountPerUserAndDefault
FROM @user AS u
LEFT JOIN @address AS a ON u.ID=a.UserID
GROUP BY u.ID,u.Name,a.IsDefault
) AS tbl
PIVOT
(
SUM(CountPerUserAndDefault) FOR PivotColumn IN([DEFAULT],[NORMAL])
) AS p
结果:
Name ID DEFAULT NORMAL
user1 1 1 NULL
user2 2 NULL 1
user3 3 1 1
user4 4 2 NULL
user5 5 NULL 0
答案 2 :(得分:1)
如果要在CTE
子句中使用别名,可以在下面使用WHERE
:
WITH cte AS (
SELECT AD.User_Id,
COUNT(AD.User_Id) AS HowManyAddresses,
SUM(
CASE WHEN
AD.IsDefault IS NULL
OR
AD.IsDefault = 0
THEN
1
ELSE
0
END
) AS DefaultEmpty,
SUM(
CASE WHEN
AD.IsDefault = 1
THEN
1
ELSE
0
END
) AS DefaultAddress
FROM dbo.Addresses AS AD
JOIN dbo.Users AS U
ON U.Id = AD.User_Id
GROUP BY AD.User_ID
ORDER BY AD.User_Id
)
SELECT *
FROM cte
WHERE /* You can use alias names here... */
GROUP BY /* You can use alias names here... */
HAVING /* You can use alias names here... */
答案 3 :(得分:0)
将其放在GROUPBY
之后:
HAVING SUM(CAST(AD.IsDefault AS INT)) > 0