Question

我有一张表Test，它的数据是：

    A   B
    1   One
    2   One
    2   Two
    3   One
    2   One
    5   Two
    2   Three
    2   Two
    2   Three
    2   Two
    2   One

现在我想要输出如下：

    A   B
    10  One
    10  One
    11  Two
    10  One
    10  One
    11  Two
    4   Three
    11  Two
    4   Three
    11  Two
    10  One

我试过

SELECT B，SUM（A）FROM Test GROUP BY A但是我得到了：

One    10
Three   4
Two    11

任何人都可以告诉我如何以最短的方式实现同样的目标，提前谢谢。

Answer 1

SELECT SUM(A) OVER (PARTITION BY B), B FROM Test

Answer 2

select t1.B, t2.sum_a
FROM Test t1
  join (select b, sum(a) as sum_a from test group by b) t2 on t1.b = t2.b

Answer 3

我会尝试创建一个子选择，其中包含总和和B列的组，然后将此子选择与当前表连接。

SELECT original.B, subquery.total 
FROM original 
INNER JOIN (
    SELECT B, SUM(A) AS total FROM original GROUP BY B) as subselect ON original.B = subquery.B

检查此其他stackoverflow：How to write subquery inside the OUTER JOIN Statement

获取重复值并在SQL中汇总第二列

3 个答案: