Question

我想查找上周的日期

SELECT *
FROM Table
Where [Date] Between '04-Jan-2016' AND '15-Jan-2016'

每次运行SQL Query时，都需要显示last week。

Answer 1

希望以下是你想要的，

--START OF LAST WEEK    
SELECT DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 0)

--END OF LAST WEEK    
SELECT DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 4)

DECLARE @input varchar(10)
--SET @input = '01/10/2016' 
SET @input = GETDATE()

--START OF LAST WEEK    
SELECT DATEADD(wk, DATEDIFF(wk, 6, 
CASE DATEPART(dw,@input)
WHEN 1 THEN DATEADD(d,-1,@input)
ELSE @input
END
), 0)

--END OF LAST WEEK     
SELECT DATEADD(wk, DATEDIFF(wk, 6, 
    CASE DATEPART(dw,@input)
    WHEN 1 THEN DATEADD(d,-1,@input)
    ELSE @input
    END
), 4)

Answer 2

---要在SQL Server中获取上一周的第一天，请使用以下代码：

SELECT DATEADD(wk,DATEDIFF(wk,7,GETDATE()),0)

- 要获得前一周的最后一天：

SELECT DATEADD(wk,DATEDIFF(wk,7,GETDATE()),4)

Answer 3

SELECT *
FROM Table
Where [Date] Between DATEADD(wk,DATEDIFF(wk,7,GETDATE()),0) 
AND DATEADD(wk,DATEDIFF(wk,7,GETDATE()),4)

Answer 4

我需要从上周一的00:00:00到前一个周日的23:59:59的范围。这是您可以获得的方式：

boolean

没有设置变量的情况相同：

SET @THIS_MONDAY = SUBDATE(DATE(NOW()), WEEKDAY(NOW()));

SELECT CONCAT(SUBDATE(@THIS_MONDAY, 7), ' 00:00:00') AS last_week_monday,
       CONCAT(SUBDATE(@THIS_MONDAY, 1), ' 23:59:59') AS last_week_sunday;

如何使用SQL Server查找星期一到星期五的最后几周日期？

4 个答案: