Question

第一个表格如下： - Car_id，Car_Model，Car_type car_id是PK

第二个表格如下： - car_id，job_number，date，current_dist，Prev_dist car_id是FK

我希望使用car_id和job_number

在第二个表格中插入新值

Answer 1

在选择查询中代替job_number，date，current_dist，Prev_dist你应该给出要插入表格的实际值

INSERT INTO Test1 (car_id, job_number, [date], current_dist, Prev_dist)
SELECT car_id,
       job_number,
       [date],
       current_dist,
       prev_dist
FROM Test
WHERE car_id = value;

Answer 2

查询将类似于

INSERT INTO second_Table (car_id, job_number, date, current_dist, Prev_dist)
SELECT car_id,
       job_number,
       [date],
       current_dist,
       prev_dist
FROM first_Table
WHERE car_id = value

在此查询job_number中，date，current_dist，prev_dist将具有实际值，car_id将来自first_Table

例如：假设job_number = 123，date =＆＃39; 2015-12-08 05：52：53.717＆＃39;，current_dist = 123，prev_dist = 234.然后查询就像

INSERT INTO second_Table (car_id, job_number, date, current_dist, Prev_dist)
SELECT car_id,
       123,
       '2015-12-08 05:52:53.717',
       123,
       234
FROM first_Table
WHERE car_id = value

Answer 3

在oracle中正常工作

在select query中代替job_number，date，current_dist，Prev_dist你应该给出要在表中插入的实际值

INSERT INTO Test1 (car_id, job_number, [date], current_dist, Prev_dist)
SELECT car_id,
       job_number,
       [date],
       current_dist,
       prev_dist
FROM Test
WHERE car_id = value;

我如何使用2行插入SQL？

3 个答案: