Question

我的查询需要帮助。我想添加一个row_number来分区我的字段，但我得到错误：错误：列“rn”不存在第22行：和rn＆lt; = 3
你在我的查询中发现了什么奇怪的东西？非常感谢！

with location as 
(select location, topcount
from pr.rankinglist_location
where topcount = 3
or (topcount = 10 and population_all > 150000)
or topcount = 25)

select store_displayname as restaurant_name,
    street,
    street_no,
    zipcode,
    city, 
    topcount,
    ROW_NUMBER() OVER (PARTITION BY city
                              ORDER BY rposition DESC) rn,
    store_id as store_id
from pr.rankinglist_store s
join
location m on m.location = s.city 
where 
statkey = '2015' 
and
topcount = 3
and rn <= 3
group by 1, 2, 3, 4, 5, 6, 7, 8
order by rposition

Answer 1

无法访问别名，WHERE子句中不允许使用窗口函数。使用派生表：

...
select *
from (
    select 
        store_displayname as restaurant_name,
        street,
        street_no,
        zipcode,
        city, 
        topcount,
        ROW_NUMBER() OVER (PARTITION BY city
                          ORDER BY rposition DESC) rn,
        store_id as store_id
    from pr.rankinglist_store s
    join location m on m.location = s.city 
    where statkey = '2015' 
    and topcount = 3
    group by 1, 2, 3, 4, 5, 6, 7, 8
    order by rposition
    ) sub
where rn <= 3;

PostgreSQL：row_number：错误：列“rn”不存在

1 个答案: