Question

从我的Java应用程序中，我尝试将重点放在Windows中的另一个打开的应用程序上，然后发送一些KeyEvent。一切正常，直到第二个窗口打开（由于我发送的KeyEvents并且是正常的预期行为）在上述应用程序中。当第二个窗口打开时，我的代码中的下一个KeyEvents不再执行。有什么帮助吗？

import java.awt.AWTException;
import java.awt.Robot;
import java.awt.event.KeyEvent;
import java.io.IOException;

public class RobotANB {

    public static void main(String[] args) throws AWTException, IOException {

        Runtime.getRuntime().exec("[path to EXE]");

        Robot robot = new Robot();

        robot.delay(20);

        robot.keyPress(KeyEvent.VK_CONTROL);
        robot.delay(20);
        robot.keyPress(KeyEvent.VK_N);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_N);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_CONTROL);
        robot.delay(20);

        robot.keyPress(KeyEvent.VK_ALT);
        robot.delay(20);
        robot.keyPress(KeyEvent.VK_D);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_D);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_ALT);
        robot.delay(20);

        // S
        robot.keyPress(KeyEvent.VK_S);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_S);
        robot.delay(20);

        // Second window in other application opens here
        // Code below no longer executed and should be
        // executed in the second window

        robot.keyPress(KeyEvent.VK_TAB);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_TAB);
        robot.delay(20);

        robot.keyPress(KeyEvent.VK_TAB);
        robot.delay(20);
        robot.keyRelease(KeyEvent.VK_TAB);
        robot.delay(20);            

    }
}

Answer 1

添加1000的延迟解决了问题

...
// S
robot.keyPress(KeyEvent.VK_S);
robot.delay(20);
robot.keyRelease(KeyEvent.VK_S);
robot.delay(1000);

// Second window in other application opens here
// Code below no longer executed and should be
// executed in the second window

robot.keyPress(KeyEvent.VK_TAB);
robot.delay(20);
robot.keyRelease(KeyEvent.VK_TAB);
robot.delay(20);
...

java专注于其他应用程序

1 个答案: