Question

我试过了：

这在我的手机上不起作用： Trying to start a service on boot on Android

这也无法正常工作： http://www.compiletimeerror.com/2014/12/android-autostart-app-after-boot-with.html#.VpL6sxWLTIU

还有一些我再也找不到的。有人可以发布一个代码的工作示例，它将使用默认的HelloWorld xml布局启动MainActivity吗？

代码：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.example"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk
        android:minSdkVersion="8"
        android:targetSdkVersion="21" />

    <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />

    <application
        android:allowBackup="true"
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >
        <receiver android:name=".MyBroadcastReceiver" >
            <intent-filter>
                <action android:name="android.intent.action.BOOT_COMPLETED" />
            </intent-filter>
        </receiver>

        <activity
            android:name=".MyService"
            android:label="@string/title_activity_my_service" >
        </activity>
    </application>

</manifest>

package com.example;

import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;

public class MyBroadcastReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context context, Intent intent) {
        Intent startServiceIntent = new Intent(context, MyService.class);
        context.startService(startServiceIntent);
    }
}

package com.example;

import android.app.Activity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;

public class MyService extends Activity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my_service);
    }
}

Answer 1

首先：创建一个BroadcastReceiver，onReceive（Context context，Intent intent），启动你要在这个方法中启动的app

    public class BootBroadcastReceiver extends BroadcastReceiver { 
   @Override  
   public void onReceive(Context context, Intent intent) {  
       xxx.class is the app you want to start
       Intent service = new Intent(context,XXXclass);  
       context.startService(service);  
       Log.v("TAG", "you want to startup this app.....");          


  Intent intent = getPackageManager().getLaunchIntentForPackage(packageName);

context.startActivity（intent）;

   }     }

其次：配置接收器和intent-filter

<receiver android:name="BootBroadcastReceiver"> <intent-filter> <action android:name="android.intent.action.BOOT_COMPLETED"></action> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </receiver>

三，添加权限

 <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />

如何在Android上启动应用程序？

1 个答案: