Question

我有三列被返回第一列是系统生成的“ID”列，第二列是仓库，第三列是仓库在该ID上显示的总和。有重复的ID我试图弄清楚如何获取仓库的最大数量并获得该ID上最大的仓库，例如：

id  WH  Count   
TRL0520841  6   2   Takes the greatest WH based on the greatest QTY 
TRL0520841  2   2   
TRL0520841  5   1   
TRL0525482  6   15  Takes the greatest WH based on the greatest QTY
TRL0525482  2   9

换句话说，TRL0520841的结果为6，而TRL0525482的结果为6

    select *
from (select ar2.trlr_id,
            to_number(ar2.area) areanum,
            ar2.con
       from (select ar1.trlr_id,
                    ar1.area,
                    count(ar1.area) con
               from (SELECT t.trlr_id,
                            pm.prtnum,
                            case when pm.prtfam like 'WH%' then substr(pm.prtfam, 3, 1)
                                 else '6'
                            end area
                       FROM rcvtrk rt,
                            trlr t,
                            rcvlin rl,
                            prtftp pf,
                            prtftp_dtl pfd,
                            prtmst pm
                      where t.trlr_id = rt.trlr_id
                        and t.trlr_stat not in ('D', 'C')
                        and rl.trknum = rt.trknum
                        and rl.prtnum = pf.prtnum
                        and pfd.prtnum = pf.prtnum
                        and pfd.ftpcod = pf.ftpcod
                        and pf.defftp_flg = '1'
                        and pfd.uomcod = 'UL'
                        and pfd.wh_id = 'CP01'
                        AND pf.wh_id = 'CP01'
                        and pf.prtnum = pm.prtnum
                        and t.yard_loc is not null
                        and t.trlr_cod = 'RCV'
                        and t.yard_loc_wh_id = 'CP01'
                      group by t.trlr_id,
                            pm.prtnum,
                            pm.prtfam) ar1
              group by ar1.trlr_id,
                    ar1.area) ar2) ar3;

Answer 1

如果我正确理解了这个问题，您可以使用ROW_NUMBER（）来确定您希望在最终结果中保留哪些行。请注意，您可能希望将该计算的ORDER BY中的其他列包含为断路器。

SELECT
      ar3.trlr_id
    , ar3.areanum
    , ar3.con
FROM (
      SELECT
            ar2.trlr_id
          , ar2.areanum
          , ar2.con
          , ROW_NUMBER() OVER(PARTITION BY ar2.trlr_id ORDER BY ar2.areanum, ar2.con DESC) as rn
      FROM (
            SELECT
                  ar1.trlr_id
                , ar1.areanum
                , COUNT(ar1.areanum) con
            FROM (
                  SELECT
                        t.trlr_id
                      , pm.prtnum
                      , to_number(CASE
                              WHEN pm.prtfam LIKE 'WH%' THEN substr(pm.prtfam, 3, 1)
                              ELSE '6'
                        END) areanum
                  FROM rcvtrk rt
                     , trlr t
                     , rcvlin rl
                     , prtftp pf
                     , prtftp_dtl pfd
                     , prtmst pm
                  WHERE t.trlr_id = rt.trlr_id
                        AND t.trlr_stat NOT IN ('D', 'C')
                        AND rl.trknum = rt.trknum
                        AND rl.prtnum = pf.prtnum
                        AND pfd.prtnum = pf.prtnum
                        AND pfd.ftpcod = pf.ftpcod
                        AND pf.defftp_flg = '1'
                        AND pfd.uomcod = 'UL'
                        AND pfd.wh_id = 'CP01'
                        AND pf.wh_id = 'CP01'
                        AND pf.prtnum = pm.prtnum
                        AND t.yard_loc IS NOT NULL
                        AND t.trlr_cod = 'RCV'
                        AND t.yard_loc_wh_id = 'CP01'
                  GROUP BY
                        t.trlr_id
                      , pm.prtnum
                      , pm.prtfam
                  ) ar1
            GROUP BY
                  ar1.trlr_id
                , ar1.areanum
            ) ar2
      ) ar3
WHERE ar3.rn = 1
;

顺便说一下：很久以前就采用了ANSI连接语法。现在是时候停止对所有连接使用where子句了。像这样（未经测试）：

SELECT
      *
FROM rcvtrk rt
      INNER JOIN trlr t ON rt.trlr_id = t.trlr_id
      INNER JOIN rcvlin rl ON rt.trknum = rl.trknum
      INNER JOIN prtftp pf ON rl.prtnum = pf.prtnum
      INNER JOIN prtftp_dtl pfd ON pf.prtnum = pfd.prtnum
                  AND pf.ftpcod = pfd.ftpcod
      INNER JOIN prtmst pm ON pf.prtnum = pm.prtnum
WHERE t.trlr_stat NOT IN ('D', 'C')
      AND t.yard_loc IS NOT NULL
      AND t.trlr_cod = 'RCV'
      AND t.yard_loc_wh_id = 'CP01'
      AND pf.defftp_flg = '1'
      AND pf.wh_id = 'CP01'
      AND pfd.uomcod = 'UL'
      AND pfd.wh_id = 'CP01'

Answer 2

假设您的列名称为＆＃39; id＆＃39;，＆＃39; WH＆＃39;和＆＃39; Count＆＃39;，并且表名是＆＃39; dbo.Warehouse＆＃39;，您需要的查询是：

SELECT Warehouse.id, WH, Count
FROM dbo.Warehouse as Warehouse
INNER JOIN
    (SELECT id, MAX(Count) AS MaxCount
    FROM dbo.Warehouse
    GROUP BY id) as groupedWH 
ON Warehouse.id = groupedWH.id
AND Count = groupedWH.MaxCount

对于具有重复最大值的ID，这将返回所有这些行（例如，对于示例中的TRL0520841，将返回count = 2的两行）;你需要决定如何处理它。

SQL：根据第一列获取最多两列

2 个答案: