Question

我想返回一个排序列表，当request method = GET时，搜索框提供给定的查询字符串（如果它不为null）。我可以在这个CBV中做到这一点，还是我必须为这个工作定义一个新视图？

我的views.py:

class DolgozokListView(ListView):

model = Dolgozo

def get_context_data(self, **kwargs):
    context = super(DolgozokListView, self).get_context_data(**kwargs)

    return context

def get(self, request):
    search_query = request.GET.get('search_box', None)
    if (search_query is not None):
        context = super(DolgozokListView, self).object_list.filter(nev__conatains = search_query)
    else:
        context = super(DolgozokListView, self).get_context_data

    return context

但我收到以下错误：

Environment:
Request Method: GET
Request URL: http://localhost:50033/dolgozo/

Django Version: 1.9.1
Python Version: 2.7.11
Installed Applications:
('django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'app',
'DolgozoKarbantart',
'DolgozoMunkakorKarbantart',
'FelhasznaloKarbantart',
'MunkaIdoAdatKarbantart',
'MunkakorKarbantart')
 Installed Middleware:
('django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware')

Traceback:

File "C:\Python27\lib\site-packages\django\core\handlers\base.py" in                    get_response  235.                 response = middleware_method(request, response)

File "C:\Python27\lib\site-packages\django\middleware\common.py" in           process_response
 112.         if response.status_code == 404:

Exception Type: AttributeError at /dolgozo/
Exception Value: 'function' object has no attribute 'status_code'

Answer 1

def get_queryset(self):
    qs = self.model.objects.all()
    search = self.request.GET.get('search_box', None)
    if search:
        qs=qs.filter(nev__icontains=search)

    return qs

Django在基于类的视图中排序列表

1 个答案: