Question

这是我第一次使用Django并经过很长时间的Python工作。我有类方法，应该使用**kwargs接受字典但它正在响应"insertToLeadHelper() takes exactly 1 argument (2 given)"

from rest_framework.response import Response
from rest_framework.renderers import JSONRenderer
from rest_framework.parsers import JSONParser
from rest_framework.views import APIView
class test(APIView):
    """
    A view that can accept POST requests with JSON content.
    """
    parser_classes = (JSONParser,)
    renderer_classes = (JSONRenderer, )
    def insertToLeadHelper(self, **data):
        print data


    def post(self, request, format=None):
        print "here"
        self.insertToLeadHelper(request.data)
        return Response({"status" : request.data},status=status.HTTP_200_OK)

请帮忙

Answer 1

为什么使用**kwargs语法？您直接传递字典，不想将其分解为kwargs。只需接受数据字典：

def insertToLeadHelper(self, data):

Python：无法在函数中获取字典

1 个答案: