重复的问题,但我发现没有完美的答案作为解决方案。请帮我解决这个问题。
我的App.js
var routes = require('./routes/index');
var users = require('./routes/users');
var media = require('./routes/media');
var widget = require('./routes/widget');
var display = require('./routes/displays');
var device = require('./routes/deviceinfo');
app.use('/', routes);
app.use('/display', display);
var server = http.createServer(app);
var io = require('socket.io')(server);
io.set('transports', ['polling', 'websocket']);
显示路线:" routes / display.js"
我有插入显示的代码,一旦创建了显示,事件应该发送到设备列表。
Emit应该写成保存成功回调方法。
var express = require('express');
var router = express.Router();
router.post('/save', action_save_displays);
function action_save_displays(req, res){
display.save(req,body , function(err , display){
if(!err){
res.json(display);
//io.sockets.emit("displaycreated", display);
}
})
}
module.exports = routes;
如何在routes / display.js文件中传递io.sockets.emit。真的很感谢你的指导。如何将socket对象发送到路由以启用emit事件。
答案 0 :(得分:1)
你可以稍微交换一下需求,然后将socket.io传递给display.js文件
var routes = require('./routes/index');
var users = require('./routes/users');
var media = require('./routes/media');
var widget = require('./routes/widget');
var server = http.createServer(app);
var io = require('socket.io')(server);
var display = require('./routes/displays')(io); // here
var device = require('./routes/deviceinfo');
app.use('/', routes);
app.use('/display', display);
io.set('transports', ['polling', 'websocket']);
并在display.js
文件
var express = require('express');
var router = express.Router();
module.exports = function(io) {
router.post('/save', function(req, res) {
display.save(req.body , function(err, display){
if(!err){
res.json(display);
io.sockets.emit("displaycreated", display);
}
});
});
return router;
}