我已经制作了一个加载屏幕(启动画面),就像旧的C64一样。
我使用了一系列图片框,只是使用计时器和案例陈述来更改彩色图像。
switch (a)
{
case 1:
pictureBox1.Image = Properties.Resources.image1;
pictureBox8.Image = Properties.Resources.image1;
pictureBox10.Image = Properties.Resources.image1;
pictureBox2.Image = Properties.Resources.image1;
pictureBox11.Image = Properties.Resources.image1;
pictureBox9.Image = Properties.Resources.image1;
break;
case 2:
pictureBox1.Image = Properties.Resources.image2;
pictureBox8.Image = Properties.Resources.image2;
pictureBox10.Image = Properties.Resources.image2;
break;
case 3:
pictureBox1.Image = Properties.Resources.image3;
pictureBox8.Image = Properties.Resources.image3;
pictureBox10.Image = Properties.Resources.image3;
break;
case 4:
pictureBox1.Image = Properties.Resources.image4;
pictureBox8.Image = Properties.Resources.image4;
break;
case 5:
pictureBox1.Image = Properties.Resources.image5;
pictureBox8.Image = Properties.Resources.image5;
break;
case 6:
pictureBox1.Image = Properties.Resources.image6;
pictureBox8.Image = Properties.Resources.image6;
break;
case 7:
pictureBox1.Image = Properties.Resources.image7;
pictureBox8.Image = Properties.Resources.image7;
break;
case 8:
pictureBox1.Image = Properties.Resources.image8;
pictureBox8.Image = Properties.Resources.image8;
break;
}
看起来有点讨厌,我怎么能改进我的代码?
答案 0 :(得分:0)
您可以查看Iterator design pattern。您可以创建一个表示单个阶段的类,该类将具有每个图片框的属性,您可以将这些属性的值设置为资源文件中的相关项。
然后,为每个加载阶段创建该对象的实例,将它们放入集合中并编写迭代器以循环该集合。
答案 1 :(得分:0)
我改进了两件事:
将您的图片存储在一个数组中,这样您就不必每次都重复case X/imageX
。
首先处理常见问题,然后专注于特殊情况。
您可以将表单中的数组声明为" fake"不变,因为它不会改变:
private readonly static Image[] myImages = new[] {
Properties.Resources.image1,
Properties.Resources.image2,
Properties.Resources.image3,
Properties.Resources.image4,
Properties.Resources.image5,
Properties.Resources.image6,
Properties.Resources.image7,
Properties.Resources.image8
}
然后在Timer hander中使用以下代码:
Image image = myImages[a-1];
pictureBox1.Image = image;
pictureBox8.Image = image;
// special cases
if (a == 1)
{
pictureBox2.Image = image;
pictureBox11.Image = image;
pictureBox9.Image = image;
}
if (a >= 1 && a <= 3)
{
pictureBox10.Image = image;
}