Question

所以，我认为我遗漏了一些非常明显的东西，或者错误地设置了我的模型，我试图在我的博客上创建一个过滤类别slug的视图，但我的过滤器只适用于Entry slug;请参阅下面的模型以及我的观点。任何帮助将不胜感激。谢谢。

我的模特

from django.db import models
from django.core.urlresolvers import reverse
from django_markdown.models import MarkdownField


class EntryQuerySet(models.QuerySet):
    def published(self):
        return self.filter(publish=True)


class Tag(models.Model):
    slug = models.SlugField(max_length=200, unique=True)

    def __str__(self):
        return self.slug


class Category(models.Model):
    slug = models.SlugField(max_length=100, blank=False)

    def __str__(self):
        return self.slug


class Entry(models.Model):
    title = models.CharField(max_length=200)
    body = MarkdownField()
    slug = models.SlugField(max_length=200, unique=True)
    publish = models.BooleanField(default=False)
    created = models.DateTimeField(auto_now_add=True)
    modified = models.DateTimeField(auto_now=True)
    tags = models.ManyToManyField(Tag)
    category = models.ForeignKey(Category)

    objects = EntryQuerySet.as_manager()

    def get_absolute_url(self):
        return reverse("post_detail", kwargs={"slug": self.slug})

    def __str__(self):
        return self.title

    class Meta:
        verbose_name = "Blog Entry"
        verbose_name_plural = "Blog Entries"
        ordering = ["-created"]

我的观点

from django.views import generic
from . import models


class BlogIndex(generic.ListView):
    queryset = models.Entry.objects.published()
    template_name = "blog/post_list.html"


class BlogDetail(generic.DetailView):
    model = models.Entry
    template_name = "blog/post_detail.html"


# Marketing Pages
class GlamisView(generic.ListView):
    queryset = models.Entry.objects.filter(slug="glamis")
    template_name = "blog/glamis_list.html"

Answer 1

如果我理解你，你可以使用查找表达式。您的查询将如下所示：

queryset = models.Entry.objects.filter(category__slug="glamis")

过滤Django Queryset

1 个答案: