如何在列表视图中输入项目并在显示描述的另一页面中显示新的GUI？

Question

String[] price ={
        "RM9.50",
        "RM6.50",
        "RM10.80",
        "RM80.20",
        "RM100.60",
        "RM50.10",
        "RM12.30",
        "RM90.50"
};
    String[] itemname ={
            "Safari",
            "Camera",
            "Global",
            "FireFox",
            "UC Browser",
            "Android Folder",
            "VLC Player",
            "Cold War"
    };

Integer[] imgid={
        R.drawable.pic1,
        R.drawable.pic2,
        R.drawable.pic3,
        R.drawable.pic4,
        R.drawable.pic5,
        R.drawable.pic6,
        R.drawable.pic7,
        R.drawable.pic8,
};
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main_activity);
    inputSearch = (EditText) findViewById(R.id.inputSearch);

    CustomListAdapter adapter=new CustomListAdapter(this, itemname, imgid, price);
    list=(ListView)findViewById(R.id.list);
    list.setAdapter(adapter);




    list.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                                int position, long id) {
            // TODO Auto-generated method stub
            String Slecteditem = itemname[+position];
            Toast.makeText(getApplicationContext(), Slecteditem, Toast.LENGTH_SHORT).show();

        }
    });
}  //main actiivty

这是主函数调用的自定义列表适配器。代码显示了所有项目的列表。但是，我想点击其中一个列表项以显示包含更多详细说明的新页面。第一张图显示了列表视图，第二张图是更详细的描述。

public CustomListAdapter(Activity context, String[] itemname, Integer[] imgid, String[] price) {
    super(context, R.layout.mylist, itemname);
    // TODO Auto-generated constructor stub

    this.context=context;
    this.itemname=itemname;
    this.imgid=imgid;
    this.price=price;
}

public View getView(int position,View view,ViewGroup parent) {
    LayoutInflater inflater=context.getLayoutInflater();
    View rowView=inflater.inflate(R.layout.mylist, null,true);

    TextView txtTitle = (TextView) rowView.findViewById(R.id.item);
    ImageView imageView = (ImageView) rowView.findViewById(R.id.icon);
    TextView extratxt = (TextView) rowView.findViewById(R.id.textView1);

    txtTitle.setText(itemname[position]);
    imageView.setImageResource(imgid[position]);
    extratxt.setText(price[position]);
    return rowView;

};

}

Answer 1

您可以覆盖onListItemClick方法并启动一个新类。您也可以使用putExtra（）将数据传递给新的Activity

if(isset($_GET['page']))
{
   $page = $_GET['page'];
   echo $page;
   //your code
}