我在计算机世界里很新鲜，并开始研究c。 现在我正在构建一个关于生成代码的小项目（如下所示）：
我的主要人物：
#include <stdio.h>
#include "connect.h"
#define EASY 20
#define NORMAL 15
#define HARD 10
#define CRAZY 30
int main ()
{
int choice = 1;
char enter, returnV;
system("cls");
printf("Welcome to ""THE MAGSHIMIM CODE BREAKER""!!!\n");
printf("\n");
printf("A secret password was chosen to protect the credit card of Pancratius,\nthe descendant of Antiochus\n");
printf("Your mission is to stop Pancratius by revealing his secret password.\n");
printf("the rules are the follows:\n");
printf("\n");
printf("1. In each round you try to guess the secret password (4 distinct digits)\n");
printf("2. After every guess you'll receive two hints about the password");
printf("\nHITS the number of digits in your guess witch were exactly right.\n");
printf("MISSES the number of digits in your guess witch belong to the password but weremiss-placed\n");
printf("3 - if you'll fail to guess the password after a certain number of rounds \tPancratius will buy all the gift to Hanukkah!!!\n");
printf("\n");
printf("Press Enter to continue...\n");
enter = getch();
if (enter = '\n'){
do{
system("cls");
printf("please choose level:\n");
printf("1 - easy (20 rounds)\n");
printf("2 - normal (15 rounds)\n");
printf("3 - hard (10 rounds)\n");
printf("4 - crazy (random number of rounds 5-25)\n");
printf("Make a choice:");
_flushall();
scanf("%1d",&choice);
if (choice == 1 || choice == 2 || choice == 3 || choice == 4 ){
switch(choice){
case (1):
system("cls");
returnV = levels(EASY);
break;
case (2):
system("cls");
returnV = levels(NORMAL);
break;
case (3):
system("cls");
returnV = levels(HARD);
break;
case (4):
system("cls");
returnV = levels(CRAZY);
break;
switch(returnV){
case('y'):
break;
case('n'):
return 0;
break;
}
}
}
else if (choice != 1 || choice != 2 || choice != 3 || choice != 4 ){
system("cls");
printf("please choose level:\n");
printf("1 - easy (20 rounds)\n");
printf("2 - normal (15 rounds)\n");
printf("3 - hard (10 rounds)\n");
printf("4 - crazy (random number of rounds 5-25)\n");
printf("Make a choice:");
_flushall();
scanf("%1d",&choice);
}
} while (returnV != 'n');
}
system("PAUSE");
}
要连接的头文件：
char levels (int level);
“级别”功能：
#include <stdio.h>
#include "connect.h"
#include <time.h>
#include <stdlib.h>
char cases (int myCase, char crazyl);
char levels (int level) {
char crazyl = 'n',playerChoice;
switch (level){
case (20):
playerChoice = cases (level,crazyl);
printf ("\n%c\n",playerChoice);
return playerChoice;
break;
case (15):
playerChoice = cases (level,crazyl);
return playerChoice;
break;
case (10):
playerChoice = cases (level,crazyl);
return playerChoice;
break;
case (30):
crazyl = 'x';
level = rand() % (25 - 5 + 1);
playerChoice = cases (level,crazyl);
return playerChoice;
}
}
int ranGen (int code1,int code2, int code3, int code4);
char cases (int level,char crazyl)
{
unsigned int check;
char choise = 't',code1,code2,code3,code4;
if(level > 0){
while (level > 0){
if(crazyl == 'n'){
printf("Write your guess (only 1-6, no ENTER is needed) [%d guess left]\n",level);
}
else if (crazyl == 'x'){
printf("Write your guess (only 1-6, no ENTER is needed) [xxx guess left]\n");
}
code1 = getch();
printf("%c",code1);
code2 = getch();
printf("\t%c",code2);
code3 = getch();
printf("\t%c\t",code3);
code4 = getch();
printf("%c\n",code4);
if(code1 > '0' && code1 < '7' && code2 > '0' && code2 < '7' && code3 > '0' && code3 < '7' && code4 > '0' && code4 < '7'){
check = ranGen(code1,code2,code3,code4);
level--;
} else {
printf("\nnot a good number only numbers between 1-6\n");
level--;
}
if (level == 0) {
printf("FOR GOD SAKE WE LOST!!!\n");
printf("The secret password was:\n");
while (choise != 'y' || choise != 'n') {
if (choise != 'y' || choise != 'n') {
printf("keep playing? (y/n):");
_flushall();
scanf("%1c",&choise);
if (choise == 'y' || choise == 'n' ) {
return choise;
} else {
continue;
}
}
}
}
}
}
}
int ranGen(int code1,int code2, int code3, int code4) {
unsigned int ranCode[3],check,code[3];
code[0] = (int) code1 - 48;
code[1] = (int) code2 - 48;
code[2] = (int) code3 - 48;
code[3] = (int) code4 - 48;
do {
ranCode[0] = rand() % (6 - 1 + 1);
ranCode[1] = rand() % (6 - 1 + 1);
ranCode[2] = rand() % (6 - 1 + 1);
ranCode[3] = rand() % (6 - 1 + 1);
} while (code[0] != ranCode[0] || code[1] != ranCode[1] || code[2] != ranCode[2] || code[3] != ranCode[3]);
}
现在我的问题在于“水平”粘贴的ranGen功能。
我需要在1-6之间生成4个不同的随机数 （1234是好的，1878不行，2234也不行）并且用户将猜测数字，而如果他做了正确的数字，我可以说：
generated code = 2345
guess = 1364
用户将获得：1 HIT和1 MISS，而如果用户输入2222，他将获得1 HIT和3 MISSES。
现在我很失落，任何帮助都会很棒。
答案 0 :(得分：0)
我在你的ranGen（）函数中看到了问题......
你有......unsigned int ranCode [3]，check，code [3];
ranCode [3]为您提供该数组中的3个元素。数组元素从零开始计数，这样就可以得到ranCode [0]，ranCode [1]和ranCode [2]。如果你想要ranCode [3]和代码[3]，那么你需要将上面一行改为......
unsigned int ranCode [4]，check，code [4];
它为您提供4个元素，编号从0到3（0,1,2和3等于4个数字）。
我也不确定你要做什么......
ranCode [0] = rand（）％（6 - 1 + 1）;
...在您的程序中，它将首先评估括号内的内容，因此6 - 1 = 5，+ 1 = 6.所以从本质上讲，该行也将看起来像ranCode [0] = rand（） ％6;到编译器并将给出一个从0到5的数字。如果你想在结果中添加一个，你可以使用：ranCode [0] =（rand（）％6）+ 1;，这将首先执行随机数，然后为它添加1到6（这是我认为你想要的骰子卷？）。
无论如何，你将code4传递给一个不存在的元素，超出范围并可能在某处破坏内存，这会导致未定义的行为，可能导致系统崩溃或影响另一个变量的内存等。