Question

我有一个JSON对象，结构如下......

var headings = ["staffId","forename","surname"];
var staff = [["1","Joe","Bloggs"],["2","Stack","Overflow"]];

任何人都可以建议我如何检索键和值，并添加到JavaScript或JQuery中的数组。例如......

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Answer 1

对于一个这样的JSON对象，它将是

var json =  [{"staffId":4,"forename":"Testf","surname":"Tests","location":"Testl","phoneNumber":"00000000000","email":"Teste"}];

var headings = Object.keys(json[0]);
var staff = [];
for ( var key in json[0] )
{
   staff.push( json[0][ key ] );
}
console.log( headings );
console.log( staff );

对于多个，你需要像

那样迭代它们

for ( var counter = 0; counter < json.length; counter++ )
{
  var jsonObj = json[ counter ];
  //same code for all json objects as above
}

Answer 2

如果我理解正确，你想做这样的事情：

var data = [
    {
        'staffId': 1,
        'forename': 'Joe',
        'surname': 'Bloggs',
        'location': 'Testl1',
        'phoneNumber': '0770....',
        'email': 'Teste1'
    },
    {
        'staffId': 4,
        'forename': 'Testf',
        'surname': 'Tests',
        'location': 'Testl',
        'phoneNumber': '07702671940',
        'email': 'Teste'
    }
];

var headings = ["staffId","forename","surname"];

var result = data.map(function(item) {
    return headings.map(function(heading) {
        return item[heading];
    });
});

console.log(result);

您可以使用Array.prototype.map()映射/转换数组。

Answer 3

您可以使用jQuery解析Json

var json = $.parseJSON(data);

调用值

alert(json.name);

从json对象中检索值

3 个答案: