mysql_query（）期望参数1为字符串，给定资源

Question

1. $abc = mysql_fetch_array($result);
     if (!$result)
        die("Error: Data not found..");        
   
   $name=$abc['name'] ;
   $email= $abc['email'] ;                 
   
   
   $sql = "UPDATE example SET name ='$name', email ='$email' WHERE id = '$id'";
       if(mysql_query($con, $sql)) //Error
           Echo "Record Update successfully";
       else
           Echo "ERROR: could not able to execute $sql".mysql_error($con); 
   
   mysql_close($con);
   

Answer 1

以这种方式更新您的代码：

$sql = "UPDATE example SET name = $name,email = $email WHERE id = $id";
mysql_query($sql,$con);

Answer 2

您需要在mysql_query函数中交换$ con和$ que参数。

http://php.net/manual/en/function.mysql-query.php

Answer 3

你必须用$ con

替换$ sql

if(mysql_query($sql, $con))
       {
        Echo "Record Update successfully";
       } 
       else
       {
        Echo "ERROR: could not able to execute $sql".mysql_error($con);
       }

Answer 4

您可以使用mysqli，这是具有更多安全功能的新版本的mysql，但您必须将所有代码单元化以使用mysql或mysqli

mysqli_query($connection,$query);

OR

mysql_query($query,$connection);

无论何时使用mysqli，都应将参数1设置为连接资源