获取值> gt的总行数和行数2使用groupby

Question

如何使用值＆gt;计算行的大小和数量2用于以下数据框：

a

，输出应为

df
     kpi_date    cell_name         call_drop
    2016-01-01    bgl_2345            0.2
    2016-01-01    bgl_2346            2.3
    2016-01-01    blg_2347            0.3
    2016-01-02    bgl_2345            1.4
    2016-01-02    bgl_2346            2.5
    2016-01-03    bgl_2347            2.7

请指导

Answer 1

逐步进行：

grouped = df.groupby('kpi_date')
count = grouped['call_drop'].count()
greater2 = grouped.apply(lambda x: x['call_drop'][x['call_drop']> 2].count())
greater2.name = 'call_Drop>2'
print(pd.concat([count, greater2], axis=1))

输出：

            call_drop  call_Drop>2
kpi_date                          
2016-01-01          3            1
2016-01-02          2            1
2016-01-03          1            1

Answer 2

您可以参考Returning a Series to propagate names，其中包含以下代码：

gd = df.groupby('kpi_date')
print(gd['call_drop'].apply(lambda x: {'call_drop':x.count(), 'call_drop>2':x[x>2].count()}).unstack())

Output:
          call_drop  call_drop>2
kpi_date                        
1/1/2016          3            1
2/1/2016          2            1
3/1/2016          1            1