Question

我有一个使用Speech to Text的项目，您可以在不打字的情况下发送短信并通过语音发送。现在我有一个代码，用户说出他/她想要发送的单词/句子，我也有一个确认，用户需要说“是”才能发送。

现在我的代码是

//Voice recording message via mic
public void promptSpeechInput() {
    //Create intent to recognize the speech and we have putExtra to have other values than voice itself
    Intent i = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
    i.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
    i.putExtra(RecognizerIntent.EXTRA_LANGUAGE, Locale.getDefault());
    i.putExtra(RecognizerIntent.EXTRA_PROMPT, "Say something!");

    //StartActivityForResult always binded by intent, getting the result from previous intent


    try {
        startActivityForResult(i, 100);
    } catch (ActivityNotFoundException e) {
        Toast.makeText(this, "You device does not support LazySpeech App", Toast.LENGTH_LONG).show();
    }

}

这是我的 onActivityResult 代码

@Override
protected void onActivityResult(int request_code, int result_code, Intent data) {
    super.onActivityResult(request_code, result_code, data);

    switch (request_code) {
        case 100:
            if (result_code == RESULT_OK && data != null) {
                ArrayList<String> result = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
                sampleTextView.setText(result.get(0));
                String getMessage = sampleTextView.getText().toString();
                messageHolder(getMessage);

                String getAnswer = sampleTextView2.getText().toString();

                switch(getAnswer){
                    case"yes":
                        ttsobject.speak("yes?", TextToSpeech.QUEUE_FLUSH, null);

                        sampleTextView3.setText(getMessage);
                        break;
                    case"no":
                        ttsobject.speak("No?", TextToSpeech.QUEUE_FLUSH, null);

                        break;
                    default:
                        break;
                }

            }
    }

}

这是我的确认文本

public String messageHolder(String getMessage){

    if(getMessage != ""){
        if (Build.VERSION.RELEASE.startsWith("15")) {
            ttsobject.speak("You want to send this message".concat(getMessage) + "?", TextToSpeech.QUEUE_FLUSH, null, null);
            activateMicButton();

        } else {
            ttsobject.speak("You want to send this message".concat(getMessage) + "?", TextToSpeech.QUEUE_FLUSH, null);
            activateMicButton();
        }

    }else{

        if (Build.VERSION.RELEASE.startsWith("15")) {
            ttsobject.speak("say your words again", TextToSpeech.QUEUE_FLUSH, null, null);
            activateMicButton();
        } else {
            ttsobject.speak("say your words again", TextToSpeech.QUEUE_FLUSH, null);
            activateMicButton();

        }
    }

    return getMessage;
}

例如，他/她说＆＃34;嘿，我想吃晚饭？＆＃34;。

问题是，我怎样才能得到他/她想发送的字样（嘿想要吃晚餐），因为我能得到的只是＆＃34; YES＆＃34;或＆＃34;否＆＃34;我确认的文字。

我尝试过创建类似的东西

sampleTextView2.setText(result.get(1));
String getSentence = sampleTextView.getText().toString();

我也试过制作静态字符串，把它放在globalvariable，

仍然没有运气。每当我在麦克风上说些什么时，这些话就不断变化，有谁知道如何解决这个问题？

Answer 1

您可以通过复制字符串而不是指向它的指针来保存以前的单词，就像使用全局变量一样。您可以使用以下构造函数创建新的String对象来完成此操作：

String theWords = new String(result.get(0));

然后您可以使用theWords变量来获取用户想要发送的消息。

在对Android说另一个单词后，语音到文本以获取前一个单词

1 个答案: