Question

我现在管理的网站已被破坏。我想保留内容，但从临时WordPress安装中复制所有php，txt和css文件，并使用脚本将它们移动到相应的位置。

我不知道如何制作类似这样的bash或shell脚本：

#!/usr/bash
type = [*\.php|*\.css|*\.ini|*\.txt]  

find /temporary/WordPress/ -type f -name '$type' {} + > file-paths-in-temporary-wordpress ;
egrep -o '[a-zA-Z]\.[php|css|ini|txt]' file-paths-in-temporary-wordpress > file-names-of-temporary-WordPress-Installation
find /old/installation/WordPress -type f -name '$type' {} + > file-paths-to-use-as-reference

while read $type in file-names-of-temporary-WordPress-Installation ; do        
    // locating file-names-of-temporary-WordPress-Installation in old WordPress site, copy files  from file-paths-in-temporary-wordpress to the matching locations in the old WordPress installation //

我对如何让它发挥作用感到困惑。显然，这非常不完整。

我希望的结果是将新WordPress安装中的所有php，ini，css和txt文件复制到旧WordPress站点的相应位置。

我可以使用：

find /temporary/WordPress -type f -name '*.php' -exec cp -fvr {} /old/WordPress/Installation/ + ;
find /temporary/WordPress -type f -name '*.css' -exec cp -fvr {} /old/WordPress/Installation/ + ;

...等。

有什么想法吗？

请帮忙。谢谢！

Answer 1

为什么不能搜索每个目录并在匹配时复制？

int main(){
char process[2][2][22]={
"BE 4321 AU","Avanza","BE 2345 JU","Avanza",
"BE 1453 GU","Xenia","BE 2233 FI","Gran Max",
"BE 7809 GM","Mobilio","BE 4426 BI","Ertiga"
"BE 9012 AG","Pajero","BE 9320 YU","Fortuner"};
char broken[2][2][20]={"BE 4321 AU","Avanza","BE 2345 JU","Fortuner"};
int p;
system("clear");
cout<<"Please choose list vehicle\n1. Broken Vehicle\n2. Under Repair...";
cin>>p;
if(p==1){
system("clear");
cout<<"Broken Vehicle List\n\n";
cout<<"   ID Car\tMerk Car"<<endl;
for (int i = 0; i < 2; i += 1) {  
    cout<<i+1<<". ";
    for (int j = 0; j < 2; j += 1) {  
    cout<<process[i][j]<<"\t";  
    }  
    cout<<endl;
}
}
else if(p==2){
system("clear");
cout<<"Under Repair Vehicle List\n\n";
cout<<"   ID Car\tCar Merk"<<endl;
for (int i = 0; i < 2; i += 1) {  
    cout<<i+1<<". ";
    for (int j = 0; j < 2; j += 1) {  
    cout<<broken[i][j]<<"\t";  
    }  
    cout<<endl;
}  
}
else{
cout<<"Wrong Choose";
}
}

Answer 2

您可以先复制所有内容并删除不需要的内容：

cp -r /temporary/WordPress /old/WordPress/
find /old/WordPress/ -type f -regex ".*\.\(php\|css\|ini\|txt\)" -exec rm {} \;

这可能会留下空目录并修复出错的地方（复制你不想要的文件）。

所以正确的方法是只复制你需要的文件。首先转到/ temporary / WordPress，这样你就不需要切断那个目录了：

cd /temporary/WordPress
find . -type f -regex ".*\.\(php\|css\|ini\|txt\)" | while read file; do
   dir="/old/WordPress/${file%/*}"
   mkdir -p "${dir}" 2>/dev/null
   cp "${file}" "/old/WordPress/${file}"
done

（抱歉，未经测试）

查找并将文件从一个目录替换到另一个WordPress

2 个答案: