Question

尝试按字母顺序将数组与foreach循环合并。

<?php
$fruits = array(
    'Apple' => array('ids'=>array(1,2)),
    'Banana' => array('ids'=>array(3,4)),
    'Ananas' => array('ids'=>array(5,6))
    );

$result = array();

foreach ($fruits as $name=>$subarr) {
    $first_letter = mb_substr($name, 0, 1);

    $result[$first_letter] = $subarr;
}

的print_r（$结果）; 给我一些喜欢什么

Array
(
    [A] => Array
        (
            [ids] => Array
                (
                    [0] => 5
                    [1] => 6
                )
        )

[B] => Array
    (
        [ids] => Array
            (
                [0] => 3
                [1] => 4
            )
    )


)

而不是像

那样的smth

{{1}}

我该如何解决？

Answer 1

您在此行中每次迭代都会覆盖您的结果：

var userAuth = require('./userAuth');

//api list  
var apiMiddleware = {
    read : {
        get : {
        },

        post : {
            'login': userAuth.signin,
        }
    },
    write : {
        post : {
            'signup' : userAuth.signup,
        },

        get : {
        }
    }
}



function Api(type, method,req,res){
    this.type = type;
    this.method = method;
    this.api = api;
    this.req = req;
    this.res = res;
}


Api.prototype = {
    constructor: Api,
    init: function() {
        var self = this;
        //handle get request
        console.log(this.type,this.method,this.api);
        var apiHandler = ((apiMiddleware[this.type]||{})[this.method] || {})[this.api];

        if (apiHandler) {
            apiHandler.call(this, this.req);
        } 
        else {
            this.notFound();
        }
    }
}



//all api request will pass through this function
function handleRequest(type, method, api, req, res) {
    //to get to pass arguments in api
   // var arg = util.objToAry(arguments).slice(2, this.length);

    //create apiObject

         console.log("in api argument");

    var apiObj = new Api(type, method, api, req, res);


    // initialize api
    apiObj.init();
}

//to export handleRequest
module.exports.handle = handleRequest;

如果结果数组中的subArray不存在，只需创建一个新数组，并将$result[$first_letter] = $subarr; subArray合并到结果数组中。

ids

Answer 2

请尝试使用foreach循环。

cout<<Rice.getYear()<<endl;

显示以上代码输出，如下所示。

$fruits = array(
    'Apple' => array('ids'=>array(1,2)),
    'Banana' => array('ids'=>array(3,4)),
    'Ananas' => array('ids'=>array(5,6))
    );

$result = array();
foreach ($fruits as $name=>$subarr) {
    $first_letter = mb_substr($name, 0, 1);
    foreach($subarr as $key=>$value){
        foreach ($value as $gkey => $gvalue) {
            $result[$first_letter]['ids'][] = $gvalue;
        }

    }
}

echo "<pre>";
print_r($result);

合并多维数组的子数组，同时按字母顺序排序数组

2 个答案: