我试图通过使用变换旋转在SVG中旋转圆形元素来创建光晕效果。我使用getBox来获取要旋转的元素的中心点。当旋转发生时,旋转中心是准确的,总图像偏移并且不与矩形框对齐。我尝试了另一个螺旋路径的例子。路径对象也得到了偏移:
如何确保动画不会影响动画元素的位置?
答案 0 :(得分:2)
<svg xmlns="http://www.w3.org/2000/svg" width="250" height="250" onload="init(evt)" >
<script type="text/ecmascript">
var svgNS = "http://www.w3.org/2000/svg";
function init(evt){
if ( window.svgDocument == null ) svgDocument = evt.target.ownerDocument;
addRotateTransform('spiral', 30, 1);
}
function addRotateTransform(target_id, speed, direction){
var element_to_rotate = svgDocument.getElementById(target_id);
var my_transform = svgDocument.createElementNS(svgNS, "animateTransform");
var cx = 315.1676;
var cy = 387.68182;
my_transform.setAttributeNS(null, "attributeName", "transform");
my_transform.setAttributeNS(null, "attributeType", "XML");
my_transform.setAttributeNS(null, "type", "rotate");
my_transform.setAttributeNS(null, "dur", speed + "s");
my_transform.setAttributeNS(null, "repeatCount", "indefinite");
my_transform.setAttributeNS(null, "from", "0 "+cx+" "+cy);
my_transform.setAttributeNS(null, "to", 360*direction+" "+cx+" "+cy);
element_to_rotate.appendChild(my_transform);
my_transform.beginElement();
}
</script>
<g transform="scale(.5) translate(-100,-180)">
<path id="spiral" style="fill:none;stroke:black"
d="m 315.1676,387.68182 c 8.40748,6.17899 -4.1812,14.38161 -10.26988,13.97378 -16.49996,-1.10519 -22.18834,-21.15425 -17.67767,-34.51355 8.06853,-23.89666 37.41077,-31.03457 58.75721,-21.38155 31.32677,14.1662 40.10076,53.87255 25.08544,83.00087 -20.01306,38.82347 -70.4052,49.25812 -107.24453,28.78933 -46.35854,-25.75789 -58.46213,-86.97114 -32.49322,-131.48819 31.45184,-53.91612 103.55573,-67.69306 155.73186,-36.19711 61.48776,37.11689 76.94087,120.15192 39.90099,179.97551 -42.764,69.06871 -136.75587,86.19995 -204.21917,43.60489 C 146.08254,465.04658 127.27172,360.08053 175.42985,284.98296 229.456,200.73484 345.4085,180.24337 428.13635,233.9703 c 91.84359,59.64708 114.01657,186.59502 54.71655,276.95016"
/>
</g>
</svg>
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在上面的示例中,我将原始svg缩小为旋转螺旋。获取动画脚本的螺旋中心坐标就可以了。您可能已经注意到我从transform
元素中取出<path>
属性并将其放置在螺旋路径周围的组(<g>
)中。
将<script>
- 标签包含到SVG中对我来说是新的,因此这是一个有趣的读取(!),但 也可以在没有这样做的情况下执行此操作,例如:
<svg xmlns="http://www.w3.org/2000/svg" width="250" height="250" oonload="init(evt)" >
<g transform="scale(.5) translate(-100,-180)">
<path id="spiral" style="fill:none;stroke:black"
d="m 315.1676,387.68182 c 8.40748,6.17899 -4.1812,14.38161 -10.26988,13.97378 -16.49996,-1.10519 -22.18834,-21.15425 -17.67767,-34.51355 8.06853,-23.89666 37.41077,-31.03457 58.75721,-21.38155 31.32677,14.1662 40.10076,53.87255 25.08544,83.00087 -20.01306,38.82347 -70.4052,49.25812 -107.24453,28.78933 -46.35854,-25.75789 -58.46213,-86.97114 -32.49322,-131.48819 31.45184,-53.91612 103.55573,-67.69306 155.73186,-36.19711 61.48776,37.11689 76.94087,120.15192 39.90099,179.97551 -42.764,69.06871 -136.75587,86.19995 -204.21917,43.60489 C 146.08254,465.04658 127.27172,360.08053 175.42985,284.98296 229.456,200.73484 345.4085,180.24337 428.13635,233.9703 c 91.84359,59.64708 114.01657,186.59502 54.71655,276.95016">
<animateTransform attributeName="transform" attributeType="XML" type="rotate"
from="0 315.1676 387.68182" to="360 315.1676 387.68182" dur="30s" repeatCount="indefinite"/>
</path>
</g>
</svg>
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