我想知道如何从(groovy)Jenkins工作流脚本调用REST API。我可以执行“sh'curl -X POST ...'” - 它可以工作,但是将请求构建为curl命令很麻烦并且处理响应变得复杂。我更喜欢原生的Groovy HTTP客户端在groovy中编程 - 我应该从哪个开始?由于脚本是在Jenkins中运行的,因此可以将所有需要的依赖关系jar复制到Jenkins上的groovy安装中,因此可以理解轻量级的内容。
答案 0 :(得分:13)
有一个内置步骤可用于使用Jenkins HTTP Request Plugin来发出http请求。
插件:https://wiki.jenkins-ci.org/display/JENKINS/HTTP+Request+Plugin
来自插件github页面的示例:
def response = httpRequest "http://httpbin.org/response-headers?param1=${param1}"
println('Status: '+response.status)
println('Response: '+response.content)
答案 1 :(得分:10)
我在安装HTTPBuilder库时遇到了麻烦,因此我最终使用了更基本的URL类来创建HttpUrlConnection。
HttpResponse doGetHttpRequest(String requestUrl){
URL url = new URL(requestUrl);
HttpURLConnection connection = url.openConnection();
connection.setRequestMethod("GET");
//get the request
connection.connect();
//parse the response
HttpResponse resp = new HttpResponse(connection);
if(resp.isFailure()){
error("\nGET from URL: $requestUrl\n HTTP Status: $resp.statusCode\n Message: $resp.message\n Response Body: $resp.body");
}
this.printDebug("Request (GET):\n URL: $requestUrl");
this.printDebug("Response:\n HTTP Status: $resp.statusCode\n Message: $resp.message\n Response Body: $resp.body");
return resp;
}
/**
* Posts the json content to the given url and ensures a 200 or 201 status on the response.
* If a negative status is returned, an error will be raised and the pipeline will fail.
*/
HttpResponse doPostHttpRequestWithJson(String json, String requestUrl){
return doHttpRequestWithJson(json, requestUrl, "POST");
}
/**
* Posts the json content to the given url and ensures a 200 or 201 status on the response.
* If a negative status is returned, an error will be raised and the pipeline will fail.
*/
HttpResponse doPutHttpRequestWithJson(String json, String requestUrl){
return doHttpRequestWithJson(json, requestUrl, "PUT");
}
/**
* Post/Put the json content to the given url and ensures a 200 or 201 status on the response.
* If a negative status is returned, an error will be raised and the pipeline will fail.
* verb - PUT or POST
*/
HttpResponse doHttpRequestWithJson(String json, String requestUrl, String verb){
URL url = new URL(requestUrl);
HttpURLConnection connection = url.openConnection();
connection.setRequestMethod(verb);
connection.setRequestProperty("Content-Type", "application/json");
connection.doOutput = true;
//write the payload to the body of the request
def writer = new OutputStreamWriter(connection.outputStream);
writer.write(json);
writer.flush();
writer.close();
//post the request
connection.connect();
//parse the response
HttpResponse resp = new HttpResponse(connection);
if(resp.isFailure()){
error("\n$verb to URL: $requestUrl\n JSON: $json\n HTTP Status: $resp.statusCode\n Message: $resp.message\n Response Body: $resp.body");
}
this.printDebug("Request ($verb):\n URL: $requestUrl\n JSON: $json");
this.printDebug("Response:\n HTTP Status: $resp.statusCode\n Message: $resp.message\n Response Body: $resp.body");
return resp;
}
class HttpResponse {
String body;
String message;
Integer statusCode;
boolean failure = false;
public HttpResponse(HttpURLConnection connection){
this.statusCode = connection.responseCode;
this.message = connection.responseMessage;
if(statusCode == 200 || statusCode == 201){
this.body = connection.content.text;//this would fail the pipeline if there was a 400
}else{
this.failure = true;
this.body = connection.getErrorStream().text;
}
connection = null; //set connection to null for good measure, since we are done with it
}
}
然后我可以通过以下方式进行GET:
HttpResponse resp = doGetHttpRequest("http://some.url");
使用JSON数据的PUT使用类似于:
HttpResponse resp = this.doPutHttpRequestWithJson("{\"propA\":\"foo\"}", "http://some.url");
答案 2 :(得分:9)
Native Groovy Code,无需导入任何包:
// GET
def get = new URL("https://httpbin.org/get").openConnection();
def getRC = get.getResponseCode();
println(getRC);
if(getRC.equals(200)) {
println(get.getInputStream().getText());
}
// POST
def post = new URL("https://httpbin.org/post").openConnection();
def message = '{"message":"this is a message"}'
post.setRequestMethod("POST")
post.setDoOutput(true)
post.setRequestProperty("Content-Type", "application/json")
post.getOutputStream().write(message.getBytes("UTF-8"));
def postRC = post.getResponseCode();
println(postRC);
if(postRC.equals(200)) {
println(post.getInputStream().getText());
}
答案 3 :(得分:1)
阻止I / O调用的主线程不是一个好主意。
目前推荐将I / O操作委派给shell步骤。
另一种需要开发的方法是添加一个新步骤。顺便说一句,有an initiative添加一组通用的步骤,以便在管道脚本中安全使用,尽管完整的REST客户端拥有自己的插件。
答案 4 :(得分:0)
您是否尝试过Groovy的HTTPBuilder类? 例如:
@Grapes(
@Grab(group='org.codehaus.groovy.modules.http-builder', module='http-builder', version='0.7.1')
)
import groovyx.net.http.HTTPBuilder
import static groovyx.net.http.ContentType.*
import static groovyx.net.http.Method.*
def http = new HTTPBuilder("http://api.geonames.org/citiesJSON?north=44.1&south=-9.9&east=-22.4&west=55.2&lang=de&username=demo")
http.request(POST, JSON ) { req ->
body = []
response.success = { resp, reader ->
println "$resp.statusLine Respond rec"
}
}