我已经痛苦了几天如何登录我的Android应用程序。我想发送一个带有请求的json对象到我的Webservice。他将检查用户和密码是否正确，并将返回用户信息。我认为web服务还可以，因为当我在我的终端上执行POST时这样：
curl -i -X POST http://bomatec.be/android_login_api/login.php -d '{"password":"xxxxxx","email":"dddd@gmail.com"}'
我得到了我想要的数据：
{"error":false,"user_id":46,"name":"steven","email":"steven@gmail.com"}
我将在问题的最后发布我的webservice（php）代码。因为我关于我的问题关于SO的关于5个以上的教程和问题，我认为它可能是凭证或权限/认证的问题或其他什么？我仍然无法通过我的Android应用程序获得我的网络服务的响应。
我尝试了两种不同的类型。我现在正在使用这个：
private void checkLogin(final String email, final String password) {
pDialog.setMessage("Logging in ...");
showDialog();
final String URL = "http://bomatec.be/android_login_api/login.php";
HashMap<String, String> params = new HashMap<String, String>();
params.put("email", email);
params.put("password", password);
JsonObjectRequest req = new JsonObjectRequest(URL, new JSONObject(params),
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
String responses = response.toString();
try {
VolleyLog.v("Response:%n %s", response.toString(4));
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.e("Error: ", error.getMessage());
}
});
ApplicationController.getInstance().addToRequestQueue(req);
}
这是 ApplicationController
package info.androidhive.loginandregistration.helper;
/**
* Created by stevengerrits on 7/01/16.
*/
import android.app.Application;
import com.android.volley.RequestQueue;
import com.android.volley.toolbox.Volley;
import com.android.volley.Request;
import com.android.volley.VolleyLog;
import android.text.TextUtils;
public class ApplicationController extends Application {
/**
* Log or request TAG
*/
public static final String TAG = "VolleyPatterns";
/**
* Global request queue for Volley
*/
private RequestQueue mRequestQueue;
/**
* A singleton instance of the application class for easy access in other places
*/
private static ApplicationController sInstance;
@Override
public void onCreate() {
super.onCreate();
// initialize the singleton
sInstance = this;
}
/**
* @return ApplicationController singleton instance
*/
public static synchronized ApplicationController getInstance() {
return sInstance;
}
/**
* @return The Volley Request queue, the queue will be created if it is null
*/
public RequestQueue getRequestQueue() {
// lazy initialize the request queue, the queue instance will be
// created when it is accessed for the first time
if (mRequestQueue == null) {
mRequestQueue = Volley.newRequestQueue(getApplicationContext());
}
return mRequestQueue;
}
public <T> void addToRequestQueue(Request<T> req, String tag) {
// set the default tag if tag is empty
req.setTag(TextUtils.isEmpty(tag) ? TAG : tag);
VolleyLog.d("Adding request to queue: %s", req.getUrl());
getRequestQueue().add(req);
}
public <T> void addToRequestQueue(Request<T> req) {
// set the default tag if tag is empty
req.setTag(TAG);
getRequestQueue().add(req);
}
/**
* Cancels all pending requests by the specified TAG, it is important
* to specify a TAG so that the pending/ongoing requests can be cancelled.
*
* @param tag
*/
public void cancelPendingRequests(Object tag) {
if (mRequestQueue != null) {
mRequestQueue.cancelAll(tag);
}
}
}
我也尝试过这里提到的helperclass（这是我的旧代码）：Volley JsonObjectRequest Post request not working
但这也没有奏效。代码：
private void checkLogin(final String email, final String password) {
// Tag used to cancel the request
//String tag_string_req = "req_login";
pDialog.setMessage("Logging in ...");
showDialog();
HashMap<String, String> params = new HashMap<String, String>();
params.put("email", email);
params.put("password", password);
JsonObjectRequest req = new JsonObjectRequest("http://bomatec.be/android_login_api/login.php", new JSONObject(params),
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
VolleyLog.v("Response:%n %s", response.toString(4));
JSONObject jObj = response;
//hideDialog();
try {
boolean error = jObj.getBoolean("error");
// Check for error node in json
if (!error) {
// user successfully logged in
// Create login session
session.setLogin(true);
// Now store the user in SQLite
String uid = jObj.getString("uid");
JSONObject user = jObj.getJSONObject("user");
String name = user.getString("name");
String email = user.getString("email");
String userid = user.getString("user_id");
// Inserting row in users table
// Launch main activity
//Intent intent = new Intent(LoginActivity.class,MainActivity.class);
//startActivity(intent);
//finish();
} else {
// Error in login. Get the error message
String errorMsg = jObj.getString("error_msg");
Toast.makeText(getApplicationContext(),
errorMsg, Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
// JSON error
e.printStackTrace();
//Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.e("Error: ", error.getMessage());
}
});
ApplicationController.getInstance().addToRequestQueue(req);
}
这是 webservice PHP代码：
<?php
/**
* @author Ravi Tamada
* @link http://www.androidhive.info/2012/01/android-login-and-registration-with-php-mysql-and-sqlite/ Complete tutorial
*/
require_once 'include/DB_Functions.php';
$db = new DB_Functions();
// json response array
$response = array("error" => FALSE);
//function using_json() {
$json = file_get_contents('php://input');
$obj = json_decode($json);
//echo json_encode(array('json'=>$obj));
$email = $obj->email;
$password = $obj->password;
// get the user by email and password
echo $email;
echo $password;
$auth = $db->resolve_user_login($email, $password);
$user_name = $db->get_user_name($email);
$user_id = $db->get_user_id($email);
if ($auth) {
echo " in auth ::: ";
// use is found
$response["error"] = FALSE;
$response["user_id"] = $user_id;
$response["name"] = $user_name;
$response["email"] = $email;
echo json_encode($response);
} else {
echo " in else ::: ";
// user is not found with the credentials
$response["error"] = TRUE;
$response["error_msg"] = "Login credentials are wrong. Please try again!";
echo json_encode($response);
}
?>
这是我的调试器数据。所以你可以看到我的请求对象 （忽略/ login.php之后，这只是一个测试，如果它适用于/）
答案 0 :(得分：0)
试试这段代码，我没有凭据，所以我无法获得输出，但你可以。
我正在使用此库common-io，可以像这样导入
![http://i63.tinypic.com/155mjba.png[/IMG]](http://i63.tinypic.com/155mjba.png[/IMG]){kind=link}
compile 'org.apache.commons:commons-io:1.3.2'
以下是运行AsyncTask
private class MyTask extends AsyncTask<Void, Void, Void>{
@Override
protected Void doInBackground(Void... params) {
try {
URL url = new URL("http://www.bomatec.be/android_login_api/login.php");
HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection();
httpURLConnection.setDoOutput(true);
httpURLConnection.setRequestMethod("POST");
httpURLConnection.connect();
JsonObject jsonObject = new JsonObject();
jsonObject.addProperty("email", "dddd@gmail.com");
jsonObject.addProperty("password", "password");
DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream());
wr.writeBytes(jsonObject.toString());
wr.flush();
wr.close();
Log.d("TAG",""+ IOUtils.toString(httpURLConnection.getInputStream()));
}catch (Exception e){
e.printStackTrace();
}
return null;
}
}
输出
in else ::: {"error":true,"error_msg":"Login credentials are wrong. Please try again! da was de mail, dees is het pass "}