table.remove结束位置超出范围

时间:2016-01-08 13:07:33

标签: lua

所以我试图从我的数组中删除一个元素,但我总是以异常结束:

bad argument #1 to 'remove' (position out of bounds)

以下是代码:

    -- setup players
    players = {}
    for i=0, 3 do
        local gp = InputHandler:gamepad(i)
        if(gp:isConnected()) then
            logMessage(i .. " is connected")
            players[i] = createCharacter(i, gp)
        end
    end

-- ....

-- update players
for k, player in pairs(players) do
    logMessage("player index: " .. k)

    -- if update returns false, the played lost all lives
    if (player.update(deltaTime) == false) then
        table.remove(players, k)
    end
end

我还尝试了给定答案(https://stackoverflow.com/a/12397571/1405318)的另一个循环,同样的错误。

local i=0
while i <= #players do
    local player = players[i]
    if (player.update(deltaTime) == false) then
        table.remove(players, i)
    else
        i = i + 1
    end
end

1 个答案:

答案 0 :(得分:2)

感谢评论(现已删除),我可以修复它。 Lua索引从1开始。 所以我只需要修改我的设置:

-- setup players
players = {}
for i=0, 3 do
    local gp = InputHandler:gamepad(i)
    if(gp:isConnected()) then
        logMessage(i .. " is connected")
        players[i+1] = createCharacter(i, gp)
    end
end