Question

这是事情......我无法通过以下代码传递以下语句“此”从不打印，因此结果集为0但查询似乎正确。

查询：

从title = 1和（zipcode = 11738或zipcode = 11720或zipcode = 11727或zipcode = 11741或zipcode = 11742或zipcode = 11755或zipcode = 11763或zipcode = 11776或zipcode = 11779或zipcode的机会中选择* = 11784或zipcode = 11953）

上面的查询会返回结果。***

代码（只需切换标题和邮政编码位置，当您运行代码时仍会返回0结果）

public Opportunity[] getOpportunitiesBy(String title, String zipcode, double miles) {
    title = ""+Constants.TITLES_MAP.get(title.toLowerCase());
    String[] nearbyZipcodes = getZipcodesWithinRadius(zipcode, miles);
    StringBuilder builder = new StringBuilder();
    builder.append("(zipcode = "+zipcode+" or zipcode = "); 
    for(String otherZips : nearbyZipcodes) {
        builder.append(otherZips+" or zipcode = ");
    }
    String formattedZips = Utilities.replaceLast(builder.toString(), " or zipcode = ", ")");
    System.out.println(title+","+formattedZips);
    List<Opportunity> opportunities = this.jdbcTemplate.query("select * from opportunities where ? and title = ?",
            new Object[] { formattedZips, title}, new RowMapper<Opportunity>() {
                public Opportunity mapRow(ResultSet rs, int rowNum) throws SQLException {
                    Opportunity temp = new Opportunity();
                    System.out.println("this");
                    String[] candidateIds = rs.getString("candidateIds").split(",");
                    temp.setCandidateIds(Utilities.StringToIntArray(candidateIds));
                    temp.setCompany(rs.getString("company"));
                    temp.setId(rs.getLong("id"));
                    temp.setHtml(rs.getString("post_data"));
                    temp.setZipcode(rs.getString("zipcode"));
                    temp.setTitle(rs.getInt("title"));
                    try {
                        temp.setLogoImg(new URI(rs.getString("logo_img")));
                    } catch (Exception e) {
                    }
                    return temp;
                }
            });
    return opportunities.toArray(new Opportunity[opportunities.size()]);
}

初始println的输出（标题+“，”+ formattedZips）

1，（zipcode = 11738或zipcode = 11720或zipcode = 11727或zipcode = 11741或zipcode = 11742或zipcode = 11755或zipcode = 11763或zipcode = 11776或zipcode = 11779或zipcode = 11784或zipcode = 11953）

Answer 1

您的设置有两个问题。

首先，您不应该使用连接来创建（部分）查询，其次不是参数化查询的工作方式。参数在放入之前进行了转义，因此我怀疑查询是否符合您的预期。

SQL具有in子句而不是zipcode or zipcode or zipcode}在查询中使用单个in子句。但是，当你想要传入一个数组时，他们又有一个问题。要解决此问题，请使用NamedParameterJdbcTemplate而不是普通JdbcTemplate。然后重写查询以使用命名参数和in子句。

public Opportunity[] getOpportunitiesBy(String title, String zipcode, double miles) {
   String sql = "select * from opportunities where title = :title and zipcode in (:zips)";
   title = ""+Constants.TITLES_MAP.get(title.toLowerCase());
   String[] nearbyZipcodes = getZipcodesWithinRadius(zipcode, miles);

   Map<String, Object> params = new HashMap<>();
   params.put("title", nearbyZipcodes);
   params.put("zips", near)

   return this.jdbcTemplate.query(sql, params, new RowMapper<Opportunity>() {
       public Opportunity mapRow(ResultSet rs, int rowNum) throws SQLException {
           Opportunity temp = new Opportunity();
           System.out.println("this");
           String[] candidateIds = rs.getString("candidateIds").split(",");
           temp.setCandidateIds(Utilities.StringToIntArray(candidateIds));
           temp.setCompany(rs.getString("company"));
           temp.setId(rs.getLong("id"));
           temp.setHtml(rs.getString("post_data"));
           temp.setZipcode(rs.getString("zipcode"));
           temp.setTitle(rs.getInt("title"));
           try {
               temp.setLogoImg(new URI(rs.getString("logo_img")));
           } catch (Exception e) {
           }
           return temp;
       });

}

这样的事情应该可以解决问题，但是如果你的getZipCodesWithinRadius也使用了一个查询，你甚至可以将其用作in子句中的子选择并简单地传递给定{{1}和zipcode一样，你会有一个查询一次性得到结果（而不是2个查询和所有jdbc的东西）。

JBDCTemplate传递w /多个参数

1 个答案: