如何存储和检索我所做的javascript变量?

时间:2016-01-08 11:07:20

标签: javascript arrays forms

我正在向我发布的here发布一个后续问题,该问题已得到解决。

在我的应用程序中,我得到一个从输入表单(Gravity Forms List Field)上的动态字段中获取的值数组。可以通过以下方式创建具有相同结构的测试数组:

var entries = new Array();
entries[0] = new Array( 1, 1, 2016, "9:00", "am", "5:00", "pm");
entries[1] = new Array( 1, 2, 2016, "9:10", "am", "5:10", "pm");

从左到右,这些值为:月,日,年,开始时间,星期时间,结束时间,结束时间段。

由于它是动态输入 - 实际提交中可能有任意数量的子数组。

我的目标是拥有一组unix时间戳,我可以使用它来对表单提交进行验证。一个验证将是“当前日期超过上次提交日期的6个月”。

以下代码演示了我如何生成时间戳。

我正在寻找一种向我的数组添加无限数量时间戳的方法。

我也在寻找一种定位时间戳的方法,一旦我拥有它们。

// Create an array to collect timestamps
var sessions = new Array();

// Ready the Zero Prepend-er so dates are always correct
function twoDigitFormat( num ) {
    return ( num.toString().length < 2 ? "0"+num : num ).toString();
}

// Loop through entries array to get each entry array
for ( i = 0; i < entries.length; i++ ) {
  var entry = entries[i];

  // Loop through each entry array to get the values
  for ( j = 0; j < entry.length; j++ ) {
    var value = entry[j];

    // get all of the parts
    var month = twoDigitFormat(entry[0]);
    var day = twoDigitFormat(entry[1]);
    var year = entry[2];
    var stime = entry[3];
    var stimeperiod = entry[4];
    var etime = entry[5];
    var etimeperiod = entry[6];
  }

  // Make Human Timestamps for each entry array
  var sessionStartString = month+'-'+day+'-'+year+' '+stime+''+stimeperiod;
  var sessionEndString = month+'-'+day+'-'+year+' '+etime+''+etimeperiod;

  // I'm using moments.js for time handling     
  // Make Session Moments for each timestamp
  var sStartMoment = moment( sessionStartString, "MM-DD-YYYY HH:mm a");
  var sEndMoment = moment( sessionEndString, "MM-DD-YYYY HH:mm a");

  // Make UNIX format moments for each timestamp
  var sStartUnix = sStartMoment.unix();
  var sEndUnix = sEndMoment.unix();

  // Add each UNIX timestamp to the sessions array
  // How do I add arrays with a variable as a key? I don't want to 
  // specify the key. Someone should be able to create 10 entries, 
  // or 20 entries, or .. whatever count.
  sessions[0] = new Array ( sStartUnix );
  sessions[1] = new Array ( sEndUnix ); 
}

// Get the current time (and as UNIX)
var now = moment();
var nowUnix = now.unix();

// Loop through sessions
for ( l = 0; l < sessions.length; l++ ) {
    var session = sessions[l];  

  // How do I get things out of the array of timestamps? 
  // My current code results in session[key] being UNDEFINED?
  var lastSession = session[session.length-1];      

}

// Do stuff - like math, to run validations
// I know this isn't correct, but the idea will be to get
// a difference in hours
var lastNowDiff = nowUnix - lastSession;

if ( lastNowDiff > 4320 ) {
  alert('The submission date must be within 6 months.');
}

如果你有时间检查一下,我有running in a Fiddle

2 个答案:

答案 0 :(得分:1)

使用数组的推送方法。

示例:

var entries = new Array();
entries.push(new Array( 1, 1, 2016, "9:00", "am", "5:00", "pm"));

你可以像这样添加任意数量的数组。

完成小提琴:https://jsfiddle.net/jryven/ovc2f1b7/

答案 1 :(得分:0)

使用JavaScript Date对象进行解析和验证。