我希望用户输入4个密码之一来访问我的网站。着陆页是index.html,重定向页应该是home.html
我使用了以下代码,我使用if语句来哈希输入的密码,并将其与4个可接受的密码进行比较。如果匹配,那么我希望页面重定向。否则我想显示一个JS警报。
我的问题是,即使输入了错误的密码,它仍会重定向而不会发出警报。
//Take the values from the html form and assign them to variables
$ID = $_POST['name'];
$userpassword = $_POST['password'];
//Check to see if the password matches the hashes
if (md5($userpassword) === '5b5c45f1b9e444d9e441211cfb325270'
or '17434cf0d4ba816cd776ff8b0ec532f1'
or '7a94fda2a6e81a1693533e6dc8501b37'
or '2d8b2ba14eeb0ac1fe474d468b720771')
{
//Add the visitor name to our list
mysqli_query($connect, "INSERT INTO `visitor list` (`Visitor Name`) VALUES ('$ID')") or die("Error in INSERT: ".mysqli_error($connect));
echo "You have entered the correct password, congrats.";
// Redirect them to rest of site
header("Location: http://localhost:82/home.html");
die();
}
else {
echo "<script type='text/javascript'>alert('Wrong Password');</script>";
}
答案 0 :(得分:4)
The code is only doing the comparison in for the first md5 hash but you have 4 conditions you want to satisfy so you would replace your if condition with this:
$hashedPassword = md5($userpassword);
if ( $hashedPassword == '5b5c45f1b9e444d9e441211cfb325270'
or $hashedPassword == '17434cf0d4ba816cd776ff8b0ec532f1'
or $hashedPassword == '7a94fda2a6e81a1693533e6dc8501b37'
or $hashedPassword == '2d8b2ba14eeb0ac1fe474d468b720771')
The reason why it wasn't working is because the way PHP interpreted code was like this:
if (false/true or true or true or true)
The md5 strings were seen as 'true' values. A string is only false if it is empty or it is equal "0" (but that's kind of a separate topic you can read about here重新加载网页..因此有必要重复比较。
另一种方法是这样做:
if (in_array(md5($userpassword), ['5b5c45f1b9e444d9e441211cfb325270', '17434cf0d4ba816cd776ff8b0ec532f1', '7a94fda2a6e81a1693533e6dc8501b37', '2d8b2ba14eeb0ac1fe474d468b720771'])
基本上它正在检查在第二个参数中传递的数组中是否定义了md5($userpassword)
。
有关in_array的更多信息:
in_array - 检查数组中是否存在值
用法 bool in_array(混合$ needle,数组$ haystack [,bool $ strict = FALSE])