Question

我的问题是如何从PHP中的数据库中检索复选框值。以下代码无效。

C<E<P

Answer 1

更改声明，

$focus=explode(",",$row['hobby']);

要：

$hobby=explode(",",$row['hobby']);

此外，您可以使用三元运算符而不是像以下那样最小化代码：

<td>
  <input type="checkbox"  name="hobby[]"  value="Cricket"  size="17" <?php echo (in_array("Cricket",$hobby)) ? 'checked="checked" : '';?>>Cricket
  <input type="checkbox" name="hobby[]"  value="Music" size="17" <?php echo (in_array("Music",$hobby)) ? 'checked="checked" : '';?>>Music
  <input type="checkbox" name="hobby[]"  value="Reading"   size="17" <?php echo (in_array("Reading",$hobby)) ? 'checked="checked" : '';?>>Reading
</td>

另外，@ mapek建议，你的SQL将获取所有记录。

$result = mysqli_query($con,"SELECT hobby FROM simple WHERE id = id");

由于id始终等于id。

您应将其更改为：

$result = mysqli_query($con,"SELECT hobby FROM simple WHERE id = '$id'");

使用数组最小化此代码的另一个版本：

<td>
<?php
$hobbies = array('Cricket', 'Music', 'Reading');
if (! empty($hobbies)) {
  foreach ($hobbies as $myHobby) {
    $checked = (in_array($myHobby, $hobby)) ? 'checked="checked"' : '';
?>
<input type="checkbox" name="hobby[]" value="<?php echo $myHobby;?>" size="17" <?php echo $checked;?>><?php echo $myHobby;?>
<?php
    }
}
?>
</td>

Answer 2

试试这个：需要进行许多更改

<td>Hobby</td>
    <?php
        $id= 1; // your input id value
        $result = mysql_query("SELECT hobby FROM simple WHERE id = $id"); 
        while($row = mysql_fetch_array($result))
       {
        $hobby=explode(",",$row['hobby']);

    ?>    
    <td><input type="checkbox"  name="hobby[]"  value="Cricket"  size="17"   <?php if(in_array("Cricket",$hobby)) echo 'checked="checked"'; ?> >Cricket
         <input type="checkbox" name="hobby[]"  value="Music" size="17" <?php if(in_array("Music",$hobby)) echo 'checked="checked"'; ?> >Music
         <input type="checkbox" name="hobby[]"  value="Reading"   size="17" <?php if(in_array("Reading",$hobby))  echo 'checked="checked"'; ?> >Reading
         <input type="checkbox" name="hobby[]"  value="Study" size="17" <?php if(in_array("Study",$hobby))  echo 'checked="checked"'; ?> >Study</td>
       <?php
       }
       ?>
</tr>

Answer 3

在

中更改变量名称

<iframe src="http://www.google.com"></iframe>

从<?php if(in_array("Cricket",$hobby)) { ?>到$hobby

Answer 4

$newArray = explode(",",$result['hobbies']);
<input type="checkbox" name ="hobbies[]" value ="reading" <?php if(in_array("reading",$newArray)){ echo "checked";} ?>
<input type="checkbox" name ="hobbies[]" value = "games" <?php if(in_array("games",$newArray)){ echo "checked";}?>>`
<input type="checkbox" name ="hobbies[]" value = "coding"  <?php if(in_array("coding",$newArray)){ echo "checked";} ?>

如何在PHP中从数据库中检索复选框值

4 个答案: