Question

我有这张桌子：

AccountingEntry

ID | DateAdded | Credit | Debit | Collections | Withdrawal | WholeSellerId
1  | 2016-01-08| 1000.00| 0.00  | 0.00        | 0.00       | Sample1
2  | 2016-01-08| 0.00   | 200.00| 0.00        | 0.00       | Sample1
3  | 2016-01-08| 0.00   | 0.00  | 300.00      | 0.00       | Sample1
4  | 2016-01-08| 0.00   | 0.00  | 0.00        | 500.00     | Sample1
5  | 2016-01-08| 300.00 | 0.00  | 0.00        | 0.00       | AnotherSample
6  | 2016-01-08| 0.00   | 200.00| 0.00        | 0.00       | AnotherSample

我想要实现的是获得目前的问责制和以前的问责制。＆＃34;现在的责任＆＃34;是：从FromDate到ToDate 以及之前的问责制＆＃34;是：在FromDate之前添加的任何总和。

我有这样的声明：

with 
cte1 as
(select ae1.WholeSellerId as 'wholeseller', isnull((sum(isnull(ae1.Withdrawals,0)) + sum(isnull(ae1.Credit,0))) - (sum(isnull(ae1.Debit,0)) + sum(isnull(ae1.Collections,0))),0) as 'previous_accountability' 
from AccountingEntry ae1
where ae1.DateAdded < '2016-01-08'
group by WholeSellerId),

cte2 as 
(select ae2.WholeSellerId as 'wholeseller2', isnull((sum(isnull(ae2.Withdrawals,0)) + sum(isnull(ae2.Credit,0))) - (sum(isnull(ae2.Debit,0)) + sum(isnull(ae2.Collections,0))),0) as 'present_accountability' 
from AccountingEntry ae2 
where ae2.DateAdded between '2016-01-08' and '2016-01-09'
group by WholeSellerId)

select cte1.wholeseller as 'wholeseller', isnull(cte1.previous_accountability,0) as 'previous accountabiliy', isnull(cte2.present_accountability,0) as 'present accountability' 
from cte1
full join cte2 on cte1.wholeseller=cte2.wholeseller2

结果如下：

wholesellerId  | previous accountability | present accountability
NULL           | 0.00                    | 1000
NULL           | 0.00                    | 100

整个商家是NULL，因为在第一个表cte1中，FromDate之前没有记录。如果在第一个表cte1中没有记录，那么你能告诉我怎么做整个卖家不会是NULL，然后在第二个表cte2中使用fullsellerId吗？当我使用 LEFT JOIN 而不是 FULL JOIN 时，会发生同样的事情。

Answer 1

也可以使用isnull作为id：

select isnull(cte1.wholeseller, cte2.wholeseller) as 'wholeseller'

从单个表中获取数据，但将其视为两个表

1 个答案: