Question

我在尝试使用MySQLdb插入表时遇到错误，无法弄明白。我查找了如何捕获错误，但是当我添加代码来捕获它时，当我尝试使用raise e而不是print e时，我没有得到任何其他信息，当我尝试打印时，我得到一个错误。我需要一些帮助来获取错误以给我更多细节。我会包含整个代码，万一有人非常棒，看看我哪里出错了。然后我甚至不关心错误捕获。好的，我是的，因为我相信我很快就会再次需要它。大声笑。我实际上有8列需要更新。我正在尝试使用消除过程，一次只尝试一对。像UPC，Name和其他几个插入很好，但Modl，Path和Desc导致错误。任何帮助都将受到赞赏和感谢。

# -*- coding: utf-8 -*-
# Define your item pipelines here
#
# Don't forget to add your pipeline to the ITEM_PIPELINES setting
# See: http://doc.scrapy.org/en/latest/topics/item-pipeline.html
from __future__ import print_function
from datetime import date, datetime, timedelta
import MySQLdb
#from scrapy.extensions import DropItem
#from bff.items import ItemInfo

class mySQLPipeline(object):
    def process_item(self, item, spider):

        Product = item['ProdName']      
        Path = item['ProdPath']
        UPC = item['ProdUPC']
        Modl = item['ProdModel']
        Desc = item['ProdDesc']
        Price = item['ProdPrice']
        Stock = item['InStock']
        #Ships = item['Ships']
        Name = item['StoreName']
#Not Failing during insert    Product, Price, Stock, Name
#FAILing during insert   Modl, Path, Desc, 



        db = MySQLdb.connect(user='****', passwd='****',
                                      host='127.0.0.1',
                                      port=****,
                                      db='****')
        cursor = db.cursor()
 #       add_Product = ("INSERT INTO walmart_products (ProdName, StoreName) VALUES (%s, %s,)", Product, Name,)
 #       add_Product = ("INSERT INTO walmart_products, (ProdName)"
 #                      "VALUES (%s)", (Name))
 #                      "VALUES (%(Name)s)")
        add_Product = ("INSERT INTO walmart_products "
                        "(InStock, StoreName) "
                        "VALUES (%s, %s)")
                        #item['Ships'],

        data_Product = (Stock, Name)                                        

        #Add new product
        #try:
        cursor.execute(add_Product, data_Product)

        #except MySQLdb.IntegrityError, e: 
            #print e 

          # handle a specific error condition
        #except MySQLdb.Error, e:
            #raise e
          # handle a generic error condition
        #except MySQLdb.Warning, e:
            #print e        
          # handle warnings, if the cursor you're using raises them      
        #except MySQLdb.ProgrammingError, e:
            #print e

        # Make sure data is committed to the database
        db.commit()

        cursor.close()
        db.close()
        return item

Answer 1

我弄清楚发生了什么。这实际上是一些事情。其中一个我将列设置为varchar（200）并且已经超过2400个字符，因此增加它固定了它。在我的URL上没有逃避它，这导致了错误。再次感谢。 - 尼克刚刚编辑

mysqldb编程错误

1 个答案: