Question

如何在“感谢”和“真诚”之间获得刺痛文本

String emailtext= "Dear (RECIPIENT_PREFIX) (RECIPIENT_FIRST_NAME) (RECIPIENT_LAST_NAME), 
Thank you for being a part.....................more text ......

Thank you for your time. Filling out these sections with ...more     text....      for which you are chosen.

Sincerely,

xyz
adresss"

我试过了：

String pattern = "(Thank)((.|\n)*)(?=Sincerely,)";

Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(emailtext);

if (m.find( )) {
    System.out.println("Found value:" + m.group(0));
    System.out.println("Found value:" + m.group(1));
    System.out.println("Found value:" + m.group(2));
} else {
    System.out.println("NO MATCH");
}

错误显示：

java.lang.StackOverflowError的 at java.util.regex.Pattern $ CharProperty.match（Pattern.java:3692）在java.util.regex.Pattern $ Branch.match（Pattern.java:4502） at java.util.regex.Pattern $ GroupHead.match（Pattern.java:4556）在java.util.regex.Pattern $ Loop.match（Pattern.java:4683）在java.util.regex.Pattern $ GroupTail.match（Pattern.java:4615） at java.util.regex.Pattern $ BranchConn.match（Pattern.java:4466）at java.util.regex.Pattern $ CharProperty.match（Pattern.java:3694）在java.util.regex.Pattern $ Branch.match（Pattern.java:4502） at java.util.regex.Pattern $ GroupHead.match（Pattern.java:4556）在java.util.regex.Pattern $ Loop.match（Pattern.java:4683）

正确的ans应该显示：

"Thank you for being a part.....................more text ......

Thank you for your time. Filling out these sections with ...more text.... for which you are chosen."

Answer 1

尝试一下：

String pattern = "(Thank)(.*)(?=Sincerely,)";

Pattern p = Pattern.compile(pattern,Pattern.DOTALL );
....

Answer 2

那么你应该用

检查文本中是否存在这两个词

CharSequence s1 = "Thank";
CharSequence s2 = "Sincerely";
If (emailtext.contains(s1) && emailtext.contains(s2))

因此它不能抛出那种异常，那么，你可以这样做：

String s = emailtext.substring(emailtext.lastIndexOf("Thank"),
  emailtext.indexOf("Sincerely"));

两个特定单词之间的文字java

2 个答案: