Question

我有继承工作，但它不是很干。每个新的bolt类型我都必须重复代码。最好展示我的课程，然后进一步解释

我BoltSpec的父类（与紧固件有关的尺寸）

@Entity
@Table(name="BoltSpecs")
@IdClass(BoltSpecCK.class)
@DiscriminatorColumn(name="boltType" )
public abstract class BoltSpec implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private String size;

    @Id
    @Enumerated(EnumType.STRING)
    private EnumBoltType boltType;

    private BigDecimal basic_major_diameter = BigDecimal.ZERO;

和我的EnumBoltType

public enum EnumBoltType {
    CYLINDER_HEAD_CAP_SCREW("CYLINDER HEAD CAP SCREW", EnumHeadType.CYL),
    HEX_CAP_SCREW("HEX CAP SCREW", EnumHeadType.HEX),
    HEAVY_HEX_CAP_SCREW("HEAVY HEX CAP SCREW", EnumHeadType.HEX),
    HEX_BOLT("HEX BOLT", EnumHeadType.HEX),
    HEAVY_HEX_BOLT("HEAVY HEX BOLT", EnumHeadType.HEX),
    FLAT_COUNTERSUNK_HEAD_CAP_SCREW("FLAT COUNTERSUNK HEAD CAP SCREW", EnumHeadType.CONE);

然后我必须有重复的类，即HexCapScrew，HeavyHexCapScrew等和HexCapScrewSpec，HeavyHexCapScrewSpec等，即使它们具有相似的BoltSpec属性（不是数值）

public class HexCapScrew extends Bolt {
    private static final long serialVersionUID = 1L;
    private static HexCapScrewSpec spec;
    public HexCapScrew() {
        super(spec);
    }
}

public class HeavyHexCapScrew extends Bolt {
    private static final long serialVersionUID = 1L;
    private static HeavyHexCapScrewSpec spec;
    public HeavyHexCapScrew () {
        super(spec);
    }
}

...

@Entity
@DiscriminatorValue("HEX_CAP_SCREW")
public class HexCapScrewSpec extends BoltSpec implements Serializable {
    private static final long serialVersionUID = 1L;

    public HexCapScrewSpec() {
        super();
    }

    private BigDecimal flat_diameter = BigDecimal.ZERO;
    ...

@Entity
@DiscriminatorValue("HEAVY_HEX_CAP_SCREW")
public class HeavyHexCapScrewSpec extends BoltSpec implements Serializable {
    private static final long serialVersionUID = 1L;

    public HeavyHexCapScrewSpec() {
        super();
    }

    private BigDecimal flat_diameter = BigDecimal.ZERO;
    ...

此规格不同

@Entity
@DiscriminatorValue("FLAT_COUNTERSUNK_HEAD_CAP_SCREW")
public class FlatHeadCapScrewSpec extends BoltSpec implements Serializable {
    private static final long serialVersionUID = 1L;

    public FlatHeadCapScrewSpec() {
        super();
    }

    private BigDecimal cone_angle = BigDecimal.ZERO;
    ...

这里有一些示例import.sql数据

insert into BoltSpecs (basic_size, basic_major_diameter, boltType, flat_diameter) 
    values ('2-3/4', '2.75',  'HEX_CAP_SCREW',       '3.988')
    values ('3',     '3',     'HEX_CAP_SCREW',       '4.35')
    values ('3/8',   '0.375', 'HEAVY_HEX_CAP_SCREW', '0.669')

insert into BoltSpecs (basic_size, basic_major_diameter, boltType, cone_angle) 
    values ('2-3/4', '2.75',  'FLAT_COUNTERSUNK_HEAD_CAP_SCREW',       '39.77')

我在前端有一个下拉菜单，用户选择螺栓类型并需要使用适用的螺栓规格。我不想修改我的import.sql并放置螺栓头类型。我冒着为CONE类型螺栓说HEX的风险。有没有办法做多个DiscriminatorValue？像：

@Entity
@DiscriminatorValue("HEX_CAP_SCREW, HEAVY_HEX_CAP_SCREW, HEX_BOLT, HEAVY_HEX_BOLT")
public class BoltSpecHexHead extends BoltSpec implements Serializable {
    private static final long serialVersionUID = 1L;

    public BoltSpecHexHead () {
        super();
    }

    private BigDecimal flat_diameter = BigDecimal.ZERO;

...

public class BoltHexHead extends Bolt {
    private static final long serialVersionUID = 1L;
    private static BoltSpecHexHead spec;
    public BoltSpecHexHead () {
        super(spec);
    }
}

或者我如何将EnumHeadType作为鉴别器值进行ping操作？具有相似磁头的螺栓（EnumHeadType.CYL，HEX和CONE）之间的规格类似

Answer 1

我能够使用@DiscriminatorFormula

来实现解决方案

@Entity
@Table(name="BoltSpecs")
@IdClass(BoltSpecCK.class)
//@DiscriminatorColumn(name="boltType" )
@DiscriminatorFormula("case when boltType in ('CYLINDER_HEAD_CAP_SCREW') then 'HEX' 
   when boltType in ('HEX_CAP_SCREW','HEAVY_HEX_CAP_SCREW','HEX_BOLT','HEAVY_HEX_BOLT') then 'HEX' 
   when boltType in ('FLAT_COUNTERSUNK_HEAD_CAP_SCREW') then 'CONE' end")

public abstract class BoltSpec implements Serializable {

Answer 2

为什么不能你为所有这些使用相同的类（比方说Bolt）？它们看起来相似，它们共享相同的属性，它们的行为是否会改变？如果是这样，那么只需使用基于实例的螺栓类型的装饰器。

JPA继承不是DRY

2 个答案: