嘿我创建了这个模板化的Queue类,它适用于所有类型,除了由于某种原因在自身内嵌套。
这是队列类:
#ifndef QUEUE_H
#define QUEUE_H
//Queue node class.
template <class T>
class QueueNode
{
public:
T m_Data;
QueueNode *m_NextNode;
QueueNode(const T data_, QueueNode *nextValue_ = NULL)
{
m_Data = data_;
m_NextNode = nextValue_;
}
QueueNode(QueueNode *nextValue_ = NULL)
{
m_NextNode = nextValue_;
}
};
//Queue class.
template <class T>
class Queue
{
public:
////////////////////////////////////////////////////////////
// CONSTRUCTORS AND DESTRUCTORS
////////////////////////////////////////////////////////////
Queue();
~Queue();
////////////////////////////////////////////////////////////
// Error Codes
////////////////////////////////////////////////////////////
enum ERC_QUEUE
{
ERC_NO_ERROR,
ERC_QUEUE_EMPTY
};
////////////////////////////////////////////////////////////
// METHODS
////////////////////////////////////////////////////////////
//Check if queue is empty.
bool IsEmpty();
//Check if queue is empty.
int GetQueueSize();
//Clear the queue.
void Clear();
//Dequeue X nodes and delete them.
//If there the requested number of nodes to delete exceeds the number of nodes in the actual list,
//the function will return an empty list.
void Queue<T>::FlushNodes(unsigned short numNodes);
//Add an item to the end of the queue.
void Enqueue(T data_);
//Get an item from the front of the queue.
ERC_QUEUE Dequeue(T &data_);
//Get an item from the front of the queue without removing it.
ERC_QUEUE Peek(T &data_);
private:
QueueNode<T> *m_Head;
QueueNode<T> *m_Tail;
int m_Size;
};
//Template implementation
template <class T>
Queue<T>::Queue()
: m_Size(0)
{
//Create empty queue with front and rear pointing to NULL.
m_Head = m_Tail = NULL;
}
template <class T>
Queue<T>::~Queue()
{
Clear();
}
template <class T>
bool Queue<T>::IsEmpty()
{
//If front is NULL then the queue is empty.
return m_Head == NULL;
}
template <class T>
int Queue<T>::GetQueueSize()
{
return m_Size;
}
template <class T>
void Queue<T>::Clear()
{
QueueNode<T> *tmp;
//Go through each node until the end of the queue.
while (m_Head != NULL)
{
//Point tmp to next node.
tmp = m_Head->m_NextNode;
//Delete current node.
delete m_Head;
//Point front to next node.
m_Head = tmp;
}
m_Size = 0;
}
template <class T>
void Queue<T>::FlushNodes(unsigned short numNodes)
{
QueueNode<T> *tmp;
//Go through each node until the end of the queue or the number of requested
//nodes to be removed have been removed.
while (m_Head != NULL && numNodes != 0)
{
numNodes--;
m_Size--;
//Point tmp to next node.
tmp = m_Head->m_NextNode;
//Delete current node.
delete m_Head;
//Point front to next node.
m_Head = tmp;
}
}
template <class T>
void Queue<T>::Enqueue(T data_)
{
//Create new node.
QueueNode<T> *node = new QueueNode<T>(data_);
m_Size++;
//If queue is empty then point both front and rear to the new node.
if (IsEmpty())
{
m_Head = m_Tail = node;
return;
}
//Add node to the end of the queue and repoint rear to the new node.
m_Tail->m_NextNode = node;
m_Tail = node;
}
template <class T>
typename Queue<T>::ERC_QUEUE Queue<T>::Dequeue(T &data_)
{
//If queue is empty return NULL.
if (IsEmpty())
{
return Queue<T>::ERC_QUEUE_EMPTY;
}
//Save value from top node.
data_ = m_Head->m_Data;
//Point tmp to front.
QueueNode<T> *tmp = m_Head;
//Repoint front to the second node in the queue.
m_Head = m_Head->m_NextNode;
//Remove first node.
delete tmp;
//Update queue size.
m_Size--;
return Queue<T>::ERC_NO_ERROR;
}
template <class T>
typename Queue<T>::ERC_QUEUE Queue<T>::Peek(T &data_)
{
//If queue is empty return NULL.
if (IsEmpty())
{
return Queue<T>::ERC_QUEUE_EMPTY;
}
data_ = m_Head->m_Data;
return Queue<T>::ERC_NO_ERROR;
}
#endif //QUEUE_H
这是我想要做的:
Queue<int> tst;
Queue<Queue<int>> tst2;
tst.Enqueue(1);
tst.Enqueue(2);
tst.Enqueue(3);
tst2.Enqueue(tst);
所有内容都会编译,但程序在运行时崩溃。这是什么交易!?
答案 0 :(得分:1)
一个明显的错误是您使用的是不可安全复制的T
类型。
你这样做:
void Enqueue(T data_);
但如果类型T
是Queue<int>
,您认为data_
会怎样?制作副本,并且您的Queue
模板类没有正确的复制语义。它缺少用户定义的复制构造函数和赋值运算符。
崩溃发生在tst2
的析构函数中,因为这是一个Queue<Queue<int>>
,并且在析构函数调用tst2.Enqueue(tst);
之前,你已经在内存方式上进行了计算。一旦你打电话给你,你就死了(或将会)。
您在多个地方遇到相同的错误,那就是您正在复制无法安全复制的对象。
示例:
//Save value from top node.
data_ = m_Head->m_Data;
如果data_
是Queue<int>
,那么你再次陷入困境,因为将Queue<int>
分配给Queue<int>
是不行的。
因此解决此问题的方法是让您的Queue
类实现Rule of 3以确保副本有效。您需要实现这些功能:
Queue(const Queue& rhs);
Queue& operator=(const Queue& rhs);
另外,用这样的案例进行测试:
int main()
{
Queue<int> q1;
q1.Enqueue(10);
Queue<int> q2;
q2 = q1;
Queue<int> q3 = q2;
}
当main
退出时,这样的程序不应该崩溃,显示内存泄漏的迹象等。如果是,那么您还没有正确实现复制。