我有一个SignalProducer,ProducerA,它以不同的间隔发出值。我正在尝试收集SignalProducer发出的最新N值,并创建一个新的生产者ProducerB,它发出一个包含最新N值的数组。
当ProducerA发出前N个值时,ProducerB应该开始发光值,然后每次ProducerA发出一个新值时都会发出一个新数组。
有人可以帮助我吗?
答案 0 :(得分:0)
我想出了这段代码
extension SignalProducer {
/// Creates a new producer that emits an array that contains the latest N values that were emitted
/// by the original producer as specified in 'capacity'.
@warn_unused_result(message="Did you forget to call `start` on the producer?")
public func latestValues(n:Int) -> SignalProducer<[Value], Error> {
var array: [Value] = []
return self.map {
value in
array.append(value)
if array.count >= n {
array.removeFirst(array.count - n)
}
return array
}
.filter {
$0.count == n
}
}
}
答案 1 :(得分:0)
let (producerA, observerA) = SignalProducer<Int, NoError>.buffer(5)
let n = 3
producerA.take(n).collect()
.takeUntilReplacement(producerA.skip(n).map { [$0] })
.scan([], { $0.suffix(n - 1) + $1 })
.startWithNext {
print($0)
}
observerA.sendNext(1) // nothing printed
observerA.sendNext(2) // nothing printed
observerA.sendNext(3) // prints [1, 2, 3]
observerA.sendNext(4) // prints [2, 3, 4]
observerA.sendNext(5) // prints [3, 4, 5]