Question

我有这个输入文本文件bio.txt

Enter for a chance to {win|earn|gain|obtain|succeed|acquire|get} 
1⃣Click {Link|Url|Link up|Site|Web link} Below️
2⃣Enter Name
3⃣Do the submit(inside optin {put|have|positioned|set|placed|apply|insert|locate|situate|put|save|stick|know|keep} {shipping|delivery|shipment} adress)

需要定位这样的语法{win | earn | gain |获取|成功|获取|获取}并返回随机单词，例如：win

我如何在我的代码中从python中找到它：

input = open('bio.txt', 'r').read()

Answer 1

您可以在每行上使用正则表达式搜索您的模式（根据您的示例private JPanel connectResource(){ JPanel remoteResource = new JPanel(); JPanel panelSouth = new JPanel(); //jstMpd is a Vector<Vector<String>> jstMpd = getAlreadyMapped(); remoteResource.setLayout(new BorderLayout()); final JButton ResourceConnect = new JButton(); comboBox.addActionListener (new ActionListener () { public void actionPerformed(ActionEvent e) { Object lettereReadComboBox = comboBox.getSelectedItem(); final String letter = lettereReadComboBox.toString(); try { alreadyMapped = ctrIfalreadyMapped(ResourceSelected, letter, typeOfConnection, jstMpd); } catch (IOException e1) { } catch (InterruptedException e1) { } if(alreadyMapped) ResourceConnect.setIcon(new ImageIcon(path + "src/img/Disconnect.png")); else ResourceConnect.setIcon(new ImageIcon(path + "src/img/Drive-Network-Connected.png")); ResourceConnect.addActionListener( new ActionListener(){ public void actionPerformed(ActionEvent ae) { try { alreadyMapped = ctrIfalreadyMapped(ResourceSelected, letter, typeOfConnection, jstMpd); } catch (IOException | InterruptedException e1) { } if(alreadyMapped){ try { String localLetterMounted = deleteElement(ResourceSelected, letter, jstMpd); if(localLetterMounted!=""){ new E_Mapped_Drives().unmountResource(localLetterMounted); ResourceConnect.setIcon(new ImageIcon(path + "src/img/Drive-Network-Connected.png")); ResourceConnect.setActionCommand("!alreadyMapped"); } } catch (IOException e) { JOptionPane.showMessageDialog(null, "You didn't selected any Letter of Remote Resource!\n Please Re-Try"); } } else{ String letterGetted = ""; String letterMounted= ""; if(typeOfConnection.equals("RDP") || typeOfConnection.equals("VNC")){ try { letterGetted = letter; letterMounted = new E_Mapped_Drives().mountResourceWindows(ResourceSelected, letterGetted, credential); jstMpd.addElement(new Vector<String>(Arrays.asList(letterGetted, ResourceSelected,typeOfConnection,letterMounted))); ResourceConnect.setIcon(new ImageIcon(path + "src/img/Disconnect.png")); } catch (IOException e) { logger.warn("[BOTTONE-ResourceCONNECT][IOException] You didn't selected any letter!"); JOptionPane.showMessageDialog(null, "You didn't selected any Letter of Remote Resource!\n Please Re-Try"); } } else{ try { letterGetted = new E_Mapped_Drives().mountResourceLinux(ResourceSelected, credential);//, comboBox.getSelectedItem(), credential); ResourceConnect.setIcon(new ImageIcon(path + "src/img/Disconnect.png")); } catch (IOException e) { JOptionPane.showMessageDialog(null, "You didn't selected any Letter of Remote Resource!\n Please Re-Try"); } } } } }); } }); panelSouth.setBackground(getColorBackground()); remoteResource.add(comboBox, BorderLayout.NORTH); remoteResource.add(ResourceConnect, BorderLayout.CENTER); remoteResource.add(panelSouth, BorderLayout.SOUTH); return remoteResource; }）。然后，一旦找到它，只需根据您的示例将分隔符（"\{.*\}"）拆分。最后随机返回列表中的一个元素。

正则表达式doc：https://docs.python.org/2/library/re.html

Python的字符串常用操作文档（包括"|"）https://docs.python.org/2/library/string.html

获取列表的随机元素：How to randomly select an item from a list?

Answer 2

首先，您需要将文本文件读入字符串;找到模式＆＃34; {（[a-z |] +）}＆＃34;使用正则表达式，将它们拆分为＆＃34; |＆＃34;将列表作为随机单词。它可以通过以下方式实现：

import re, random
seed = []
matches = re.findall('{([a-z|]+)}', open('bio.txt', 'r').read())
[seed.extend(i.split('|')) for i in matches]
input = random.choice(seed)

python标识文本中的随机语法

2 个答案: