我目前正在尝试在jQuery UPDATE order_items o
SET DISCOUNT_AMOUNT =
(SELECT T.maxdiscount
FROM (SELECT customer_id,
o.order_id AS order_id,
D.product_id AS product_id,
D.total,
E.maxdiscount AS maxdiscount
FROM orders o,
( SELECT SUM (quantity) AS total,
order_id,
product_id
FROM order_items
GROUP BY order_id, product_id) D,
( SELECT MAX (discount_amount) AS maxdiscount,
product_id
FROM order_items
GROUP BY product_id) E
WHERE o.order_id = D.order_id
AND E.product_id = D.product_id) T
WHERE T.order_id = o.order_id AND T.product_id = o.product_id);
函数内的单个页面上生成多个Google Map元素。页面上有几个each()
元素,它们看起来像这样:
.new-venue-item
然后jQuery代码是:
<div class="new-venue-item">
<div class="image">
<div class="image">
<a href="/venue/8121_the-square-bristol-city-of-bristol" title="Discover more about The Square"><img src="http://static.weddingvenues.com/venues/200x300/Wedding-image-with-logo-rectangular.jpg" class="" width="200" height="300" alt="" title="" item-prop=""></a>
</div>
<div id="map8121" class="map" data-lng="-2.6101986" data-lat="51.4590031">
</div>
<div class="overlay">
<a href="#" class="action-btn btn-wv contact-venue trackit" data-click-type="search-contact" data-venue-id="8121" data-customer-id="4038" data-id="8121">Contact venue</a>
<a href="/venue/8121_the-square-bristol-city-of-bristol/" class="action-btn btn-white trackit" data-click-type="search-map" data-venue-id="8121" data-customer-id="4038">More info</a>
</div>
</div>
<div class="info">
<a href="/venue/8121_the-square-bristol-city-of-bristol" title="Discover more about The Square">The Square</a>
<span class="address"><span class="address"><a href="/p-544/united-kingdom/england/city-of-bristol/bristol/" title="Bristol, City of Bristol">Bristol</a>, <a href="/p-164/united-kingdom/england/city-of-bristol/" title="City of Bristol, England">City of Bristol</a></span></span>
</div>
</div>
不幸的是,这会生成一个灰色背景的空白地图元素。控制台中没有错误,并且正确地包含了Map API。有没有人以前遇到过此问题,我该如何解决?
我已经整理了jsFiddle来证明这个问题。
答案 0 :(得分:3)
在您的示例中,zoomLevel
需要更改为zoom
才能解决问题。
$('.new-venue-item').each(function() {
var $map = $(this).find('.map'),
lat = parseFloat($map.data('lat')),
lng = parseFloat($map.data('lng'));
// Hook up the map:
var mapOptions = {
scrollwheel: false,
streetViewControl: false,
mapTypeControl: false,
panControl: false,
zoomControl: false,
draggable: false,
zoom: 14, //Changed from zoomLevel
center: {
lat: lat,
lng: lng
}
};
//new google.maps.Map( document.getElementById('map8160'), mapOptions );
$(this).data('map', new google.maps.Map($map[0], mapOptions));
});
我花了一段时间才弄明白