Question

我需要在listview中搜索项目。我有简单的字符串和数组适配器数组，我在一些不同的问题及其工作中找到了代码！但是我有一个问题，这个搜索非常慢并且滞后于一个字母我有一个单词“arbuz”（其中一个是其中之一）而且我打印了一个 - 什么都没有，另外一个字母和单词搜索“a”，另一个 - 而且没有这样的单词。我希望你解开我。我怎么能改进这个搜索？我的代码：

public class FragmentWithList extends ListFragment {
    ListView mainList;
    EditText inputSearch;
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        View v = inflater.inflate(R.layout.fragment_with_list, null);
        mainList = (ListView) v.findViewById(android.R.id.list);
        inputSearch = (EditText)v.findViewById(R.id.inputSearch);
        return v;


    }
    public void onCreate(Bundle savedInstanceState){
        setHasOptionsMenu(true);
        super.onCreate(savedInstanceState);

    }
    public void onActivityCreated(Bundle savedInstanceState) {
        super.onActivityCreated(savedInstanceState);
        String values[] = new String[]{"arbuz","abrikos","banan","cup","charlie","derevo","grusha","ogurets","sliva","jabloko","volk","dom","igra","pharaon","muscle"};
        Comparator<String> ALPHABETICAL_ORDER1 = new Comparator<String>() {
            public int compare(String object1, String object2) {
                int res = String.CASE_INSENSITIVE_ORDER.compare(object1.toString(), object2.toString());
                return res;
            }
        };

        Collections.sort(Arrays.asList(values), ALPHABETICAL_ORDER1);
        final ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity(),android.R.layout.simple_list_item_1,values);
        mainList.setAdapter(adapter);
        inputSearch.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {
                adapter.getFilter().filter(s.toString());
            }

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {

            }

            @Override
            public void afterTextChanged(Editable s) {

            }
        });
    }
}

Answer 1

在afterTextChanged()方法

中添加以下代码

adapter.getFilter().filter(s.toString());

使用edittext在listview中搜索

1 个答案: