Question

我想将D, d.m.y转换为Y-m-d格式，即

echo $from_date=date('Y-m-d', strtotime(Wed, 09.12.15));

但是这给了我这个结果2016-01-13

https://app.absence.io/#/calendar/absence/new 检查此链接，我想将2016-01-01格式的日期发送到数据库

Answer 1

首先，确保您的日期字符串包含在引号中（"或'）。

其次，＆＃34;周三，09.12.15＆＃34;是不 strtotime()可以理解的有效日期格式。

date formats is listed here的完整列表。

Answer 2

您可以使用DateTime::createFromFormat()将非标准日期/时间字符串转换为DateTime对象，然后使用DateTime::format()以您首选格式创建日期/时间字符串。

例如：

<?php

$date = '09.12.15';

$dt = DateTime::createFromFormat('d.m.y', $date);

echo $dt->format('Y-m-d'); // 2015-12-09

希望这会有所帮助：）

Answer 3

Source

$date1 = date('D d/m/Y h:i:s A',strtotime('2015-06-01'));

以下是您可以使用的格式列表（Source）

Day of Month
____________
d   | Numeric, with leading zeros   01–31
j   | Numeric, without leading zeros    1–31
S   | The English suffix for the day of the month   st, nd or th in the 1st, 2nd or 15th.

Weekday
_______
l   | Full name  (lowercase 'L')    Sunday – Saturday
D   | Three letter name Mon – Sun

Month
______
m   | Numeric, with leading zeros   01–12
n   | Numeric, without leading zeros    1–12
F   | Textual full  January – December
M   | Textual three letters Jan - Dec

Year
____
Y   | Numeric, 4 digits Eg., 1999, 2003
y   | Numeric, 2 digits Eg., 99, 03

Time
____
a   | Lowercase am, pm
A   | Uppercase AM, PM
g   | Hour, 12-hour, without leading zeros  1–12
h   | Hour, 12-hour, with leading zeros 01–12
G   | Hour, 24-hour, without leading zeros  0-23
H   | Hour, 24-hour, with leading zeros 00-23
i   | Minutes, with leading zeros   00-59
s   | Seconds, with leading zeros   00-59
T   | Timezone abbreviation Eg., EST, MDT ...
Full Date/Time
c   | ISO 8601  2004-02-12T15:19:21+00:00
r   | RFC 2822  Thu, 21 Dec 2000 16:01:07 +0200

Answer 4

愿这是工作

$dob = date("d/m/Y",strtotime('09-12-2015'));

或

 $dob = date("d/m/Y",strtotime($res[$i]['date_from_datebase]));

这将以d / m / Y格式从数据库输出日期。

php 5中的日期格式转换

4 个答案: