Question

我需要一些代码来帮助我打印存储在数据网格行或SQL DB图像上的图像，我想用它做一些有用的事情。

我的观点是每次点击数据流时插入图像。

private void dataGridView1_CellClick(object sender, DataGridViewCellEventArgs e)
{
    SqlConnection con = new SqlConnection(@"Data Source=.\SQLEXPRESS;AttachDbFilename=D:\Trabalhos\AuthMyRegistery\AuthMyRegistery\Data.mdf;Integrated Security=True;Connect Timeout=30;User Instance=True");
    id_Worker_Info = Convert.ToInt32(dataGridView1.Rows[e.RowIndex].Cells["id_Worker_Info"].Value.ToString());
    SqlCommand cmd = con.CreateCommand();
    cmd.CommandType = CommandType.Text;
    cmd.CommandText = "select * from Worker where id_Worker_Info='" +id_Worker_Info+ "';";
    DataTable dt = new DataTable();
    SqlDataAdapter sda = new SqlDataAdapter(cmd);
    sda.Fill(dt);
    dataGridView1.DataSource = dt;

    foreach (DataRow dr in dt.Rows)
    {
       WorkerIdTextBox.Text = dr["id_Worker_Info"].ToString();
       NameTextBox.Text = dr["Name"].ToString();
       FnameTextBox.Text = dr["Formation_Name"].ToString();
       BirthTextBox.Text = dr["Date_of_Birth"].ToString();
    }
 }

Answer 1

假设您的数据来自字节数组，例如包含有效图像数据的blob类型：

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>

struct contact {
    char name[29];
    char number[11];
};

int main() {
    struct contact contact[100];
    int menu;
    int n = 0;
    int i, j, flag_1, flag_2, flag_3, flag_4, loop;
    char temp[29];

    do {
        loop = 0;
        printf("Phone Book\n");
        printf("==========\n");
        printf("1. Add New Contact\n");
        printf("2. View List Contact\n");
        printf("3. Search Contact\n");
        printf("4. Delete Contact\n");
        printf("5. Exit\n");
        printf("choose menu: ");
        scanf("%d", &menu); 
        system("cls");

        switch (menu) {
        case 1:

            printf("Add New Contact\n");
            do {
                flag_1 = flag_2 = 1;
                printf("Input name [1..30 char]: ");
                scanf(" %[^\n]", contact[n].name); 

                if (strlen(contact[n].name) > 30) {
                    printf("Length of name should be between 1 and 30 characters.\n");
                    flag_1 = 0;
                }

                if (!isalpha(contact[n].name[0])) {
                    printf("First letter of name should be an alphabet (A-Z od a-z).\n");
                    flag_1 = 0;
                }

            } while (flag_1 == 0 || flag_2 == 0);

            do {
                flag_3 = flag_4 = 1;
                printf("Input phone number [6..12 digits]: ");
                scanf("%s", contact[n].number); 

                if (strlen(contact[n].number) < 6 || strlen(contact[n].number) > 12) {
                    printf("Length of phone numbers should be between 6 and 12 digits.\n");
                    flag_3 = 0;
                }

                for (i = 0; i < strlen(contact[n].number); i++) {
                    if (!isdigit(contact[n].number[i])) {
                        flag_4 = 0;
                    }
                }
                if (flag_4 == 0) {
                    printf("Phone numbers should only contain digits (0-9).\n");
                }
            } while (flag_3 == 0 || flag_4 == 0);

            printf("\n");
            printf("New contact successfully added!\n\n");
            printf("Name : %s\n", contact[n].name);
            printf("Number : %s\n\n", contact[n].number);
            printf("Press Enter to continue...");
            n++;
            getchar();
            getchar();
            system("cls");
            loop = 0;
            break;


        case 2:
            printf("View List Contact\n\n");
            for (i = 0; i < n; i++) {
                for (j = 0; j < n - 1; j++) {
                    if (strcmp(contact[j].name, contact[j + 1].name) > 0) {
                        strcpy(temp, contact[j].name);
                        strcpy(contact[j].name, contact[j + 1].name);
                        strcpy(contact[j + 1].name, temp);

                        strcpy(temp, contact[j].number);
                        strcpy(contact[j].number, contact[j + 1].number);
                        strcpy(contact[j + 1].number, temp);

                    }
                }
            }
            printf("     # Name                            Phone Number\n");
            for (i = 0; i < n; i++) {
                printf("    %d %s                 %s\n", i + 1, contact[i].name, contact[i].number);
            }

            getchar();
            getchar();
            system("cls");
            loop = 0;
            break;
        }

    } while (loop == 0);
    getchar();
    return 0;
}

由您自行决定using System.IO; .. byte[] iData = (byte[])dr[yourColumnIndexOrName]; Bitmap bmp = null; if (iData != null) using (var ms = new MemoryStream(iData )) { bmp = new Bitmap(ms); } pb_image.Image = bmp; // display in a PictureBox和SizeMode的{{1}}。如果您愿意，可以测试Size。

在分配新位图之前，不要忘记清理位图：

PictureBox

单击datagridview行时，在图片框上显示图像

1 个答案: