Question

我试图在第二个活动中显示用户输入和密码，但是我不幸地登录已经停止了... 我收到一个错误java.lang.nullpointerException：尝试在空对象引用上调用虚方法'void android.widget.TextView.setText（java.lang.ChaeSequence）'。

主要课程。

public class MainActivity extends Activity implements View.OnClickListener
{

    EditText userName;
    EditText password;
    Button loginButton;

    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        userName = (EditText) findViewById(R.id.editText);
        password = (EditText) findViewById(R.id.editText2);
        loginButton = (Button) findViewById(R.id.button);
        loginButton.setOnClickListener(this);

        FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
        fab.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
                        .setAction("Action", null).show();
            }
        });
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu)
    {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.menu_main, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item)
    {
        // Handle action bar item clicks here. The action bar will
        // automatically handle clicks on the Home/Up button, so long
        // as you specify a parent activity in AndroidManifest.xml.
        int id = item.getItemId();
        //noinspection SimplifiableIfStatement
        if (id == R.id.action_settings)
        {
            return true;
        }

        return super.onOptionsItemSelected(item);
    }

    public void onClick(View view)
    {
            String userStr = userName.getText().toString();
            String passStr = password.getText().toString();
            Intent intent = new Intent(MainActivity.this, SecondAcivity.class);
            intent.putExtra("userName", userStr);
            intent.putExtra("password", passStr);
            startActivity(intent);
    }

第二类。

public class SecondAcivity extends MainActivity
{
 @Override
    protected void onCreate(Bundle savedInstanceState)
    {

            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_second_acivity);

             TextView  textView = (TextView) findViewById(R.id.textView);
             Intent intent = getIntent();
             String  userName = intent.getStringExtra("userName");
             String password = intent.getStringExtra("password");
             textView.setText("User Name: " + userName + " Password: " + password);


            FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
            fab.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View view) {
                    Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
                            .setAction("Action", null).show();
                }
            });


    }

Answer 1

你不要从Intent本身的实例中提取字符串。您需要从Intent中获取Bundle个额外内容，然后从Bundle获取字符串：

使用此功能：

Intent intent = getIntent();
Bundle extras = intent.getExtras();

String userName = "";
String password = "";

if (extras != null) {
    userName = extras.getString("userName");
    password = extras.getString("password");
}

Answer 2

当传递空值时，这将处理NullPointerException

试试：

pd.concat

Answer 3

如果ID textView 存在，请检查 R.layout.activity_second_acivity 。如果您的R.layout.activity_second_acivity中不存在R.id.textView，则texview变量将变为null。

Answer 4

您尝试将文本设置为null TextView

检查第二个活动布局文件activity_second_acivity 包含textView

Answer 5

您可以使用此功能从活动中获取字符串

String userName,password;
userName = getIntent().getExtras().getString("userName");
password = getIntent().getExtras().getString("passowrd");

Answer 6

Bundle extras = getIntent().getExtras(); 
String userName,password;


if (getIntent().hasExtra("userName")) {
    userName = extras.getString("userName");
    password = extras.getString("password");  
        }

字符串无法在第二个活动中显示

6 个答案: