Question

Bellow是我的代码，当我删除MailAddress（）的DisplayName属性时，它工作正常，但接收结束邮件在显示名称上显示EmailID，如emailID@gmail.com。

MailMessage mail = new MailMessage();
    mail.From = new System.Net.Mail.MailAddress("emailID@domainName.com");
    // The important part -- configuring the SMTP client
    SmtpClient smtp = new SmtpClient();
    smtp.Port = 587;   // [1] You can try with 465 also, I always used 587 and got success
    smtp.EnableSsl = true;
    smtp.DeliveryMethod = SmtpDeliveryMethod.Network; // [2] Added this
    smtp.UseDefaultCredentials = false; // [3] Changed this
    smtp.Credentials = new NetworkCredential(mail.From.ToString(), "password");  // [4] Added this. Note, first parameter is NOT string.
    smtp.Host = "smtp.gmail.com";
    mail.IsBodyHtml = true;
    mail.Subject = Subject;
    mail.Body = Body;
    mail.To.Add(new MailAddress(To));
    smtp.Send(mail);
    mail.Dispose();

当我添加MailAddress（）的显示名称时，我收到此错误消息。

System.Net.Mail.SmtpException：SMTP服务器需要安全连接或客户端未经过身份验证。服务器响应是：5.5.1需要身份验证。了解更多信息 System.Net.Mail.MailCommand.CheckResponse（SmtpStatusCode statusCode，字符串响应）在System.Net.Mail.SmtpTransport.SendMail（MailAddress sender，MailAddressCollection收件人，String deliveryNotify， Boolean allowUnicode，SmtpFailedRecipientException＆amp;例外）在***
的System.Net.Mail.SmtpClient.Send（MailMessage消息）

我哪里错了？

Answer 1

var client = new SmtpClient
    {
     Host = "smtp.googlemail.com",
     Port = 587,
     UseDefaultCredentials = false,
     DeliveryMethod = SmtpDeliveryMethod.Network,
     EnableSsl = true,
     Credentials = new NetworkCredential(SmtpUserName, SmtpUserPassword);
    };

client.Send(mail);

其中mail是MailMessage

的实例

private static SecureString _smtpPassword;

    public static SecureString SmtpUserPassword
    {
        get
        {
            if (_smtpPassword != null)
                return _smtpPassword;

            _smtpPassword = new SecureString();

            foreach (var c in "your password here")
                _smtpPassword.AppendChar(c);

            _smtpPassword.MakeReadOnly();

            return _smtpPassword;
        }
    }

通过电子邮件发送显示名称属性

1 个答案: