Question

目标是找出一个长数字中最常见的数字。例如，213523432455555555将返回5.

print('Question 4')



def most_frequent(number):
    analysisnumber=map(int,str(number))
    returnvalue=[0,0,0,0,0,0,0,0,0,0]
highest = 0
total2=0
for i in range(0,len(str(number))):
    returnvalue[analysisnumber[i]] = list(map(i,analysisnumber))
for i in range(0,20):
    if i < 10:
        if returnvalue[i] > highest:
            highest = returnvalue[i]
    if i > 10:
        if returnvalue[i-10] == highest:
            total2+=highest
print("The most frequent number",end="")
if total2 > highest:
    print("s are: ")
    for i in range(0,10):
        if returnvalue[i] == highest:
            print(i)
else:
    print(" is ", end="")
    for i in range(0,10):
        if returnvalue[i] == highest:
            print(i)
            break
number=int(input("Enter the number intended for analysis:"))
most_frequent(number)

我得到了

TypeError: 'int' object is not callable

错误。会爱一些帮助！

Answer 1

这样做，使用Counter：

>>> c.most_common(1)
[('2', 5)]

或者只是使用（感谢@tobias_k）：

Monitor Cassandra for memory consumption and stage throughput.

Set your Memtable thresholds low.

Access Cassandra concurrently.

Don’t store all your data in a single row.

Check for time-outs. 
What is the size of javaHeap?

Answer 2

你正在使用错误的地图功能。

returnvalue[analysisnumber[i]] = list(map(i,analysisnumber))

要映射的第一个值（来自文档）是函数）：map(function, iterable, ...)

你提供了一个int（i）。

数字中最频繁的数字

2 个答案: