Question

我有这个问题：

select 
    a.secCode, b.[Haircut (%)], c.[Absolute IDR (Miliar)] 
from 
    openquery(PDC_MYAPPS, 'select secCode from mii.secReq') a 
left join 
    (select * from RC_Saham) b on a.secCode = b.kode 
left join 
    (select * from Absolute_IDR) c on b.kode = c.[Kode Saham]
where 
    b.[Haircut (%)] is not null

union

select 
    a.code_Ic, a. PERC_HRCT, b.[Absolute IDR (Miliar)]
from 
    openquery(MANTARAY, 'select b.code_ic, a.PERC_HRCT 
                         from cminstruments a, instrument_codes b
                         where a.ID_CMI_CAPCO = b.INS_ID_INS_CAPCO') a   
left join 
    (select * from Absolute_IDR) b on a.code_Ic = b.[Kode Saham]
where 
    code_Ic in (select a.secCode 
                from openquery(PDC_MYAPPS, 'select secCode 
                                            from mii.secReq') a 
                                            left join (select * from RC_Saham) b on a.secCode = b.kode 
                                            left join (select * from Absolute_IDR) c on b.kode = c.[Kode Saham]
                                            where b.[Haircut (%)] is null)

我得到了结果：

 KODE    |HAIRCUT|  Absolutes IDR 
 MLIA     94.00         13                 
 SIMA     100.00        20             
 CTRA     20.00         300
 NRCA-W   100.00        NULL
 VINS     60.00         30   
 NRCA-W   100.00        NULL

我想直接在上面的查询中使用基于发夹值的数字填充空值。

让我们说haircut = 100然后absolutes IDR = 20。

如何在SQL查询中创建它？

Answer 1

您可以使用ISNULL()和CASE：

select 
    a.secCode, b.[Haircut (%)],
    ISNULL(c.[Absolute IDR (Miliar)], CASE b.[Haircut (%)]
        WHEN 100 then 20
        WHEN 80 THEN 40
        ELSE 0 END )

有关详细信息，请参阅MSDN on CASE。

通过查询手动输入数据到sql数据库

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