Question

无法使peewee使用最简单的示例：

from peewee import *

db = SqliteDatabase('people.db')

class Person(Model):
    name = CharField()
    birthday = DateField()
    is_relative = BooleanField()

    class Meta:
        database = db # This model uses the "people.db" database.

class Pet(Model):
    owner = ForeignKeyField(Person, related_name='pets')
    name = CharField()
    animal_type = CharField()

    class Meta:
        database = db # this model uses the "people.db" database

db.connect()
db.create_tables([Person, Pet])

我得到了这个奇怪的错误：

Traceback (most recent call last):
  File "D:\EclipseWorkspace\peewee_test.py", line 22, in <module>
    db.create_tables([Person, Pet])
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 3448, in create_tables
    create_model_tables(models, fail_silently=safe)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 4767, in create_model_tables
    m.create_table(**create_table_kwargs)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 4459, in create_table
    db.create_table(cls)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 3445, in create_table
    return self.execute_sql(*qc.create_table(model_class, safe))
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1865, in inner
    return self.parse_node(fn(*args, **kwargs))
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1577, in parse_node
    sql, params, unknown = self._parse(node, alias_map, conv)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1551, in _parse
    sql, params = self._parse_map[node_type](node, alias_map, conv)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1479, in _parse_clause
    node.nodes, alias_map, conv, node.glue)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1594, in parse_node_list
    node_sql, node_params = self.parse_node(node, alias_map, conv)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1577, in parse_node
    sql, params, unknown = self._parse(node, alias_map, conv)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1551, in _parse
    sql, params = self._parse_map[node_type](node, alias_map, conv)
  File "D:\Program Files (x86)\Python2.7.3\lib\site-packages\peewee.py", line 1481, in _parse_clause
    sql = '(%s)' % strip_parens(sql)
TypeError: Argument 's' has incorrect type (expected basestring, got str)

我已经搜索了一段时间，看起来像是cython相关的问题，有些建议将cython更新到最新的稳定版本，但我仍然遇到此错误{ {1}} 0.23.4 ，有谁知道如何解决这个问题？

Answer 1

好吧，让它工作你可以在循环中创建表

for table in [Pet, Person]: 
    db.create_table(table)

虽然我必须说我已经用较旧的Cython（0.21.1）对此进行了测试 - 我会看到更新后是否还有可能...这是可能的（0.23.4 ）。但我看到你的Python已经很老了，你可能会考虑升级（2.7.10似乎是最新的bugfix 2.7.x发布于2016.01.07）

Answer 2

找出解决方案。 basestring是一种新的字符串类型，从cython 0.20 开始，并根据peewee docs：

加速，包括重新实现的各种功能用Cython。如果是Cython，这个模块将自动构建安装。

所以基本上playhouse/_speedups.pyd是在安装过程中使用cython 0.19 构建的，之后我确实将cython更新为 0.23.4 但它不会对文件产生任何影响。

重新安装/重建peewee后，现在一切正常。

保持＆＃34;不正确的类型（预期的basetring，得到str）＆＃34;使用peewee在sqlite数据库中创建表

2 个答案: