我想知道是否有其他方法可以获得相同的图形或者可以编辑图例而无需使用" First"," Second",&#34更改所有字符串;图例"有一个新的传奇。
" First"的数据和"第二"有不同的长度。
代码是:
First <- c(71.54,76.48,77.58,63.80,66.16,73.22,70.71,72.94,73.22,69.37,70.49,72.25,70.94,71.54,71.01,68.36,70.46,69.22,75.98,73.66,72.90,75.74,73.55,79.48,76.37,64.62,65.86,70.08,73.40,79.72,57.43)
Second <- c(80.61,79.03,80.35,77.52,79.16,80.80,80.49,82.00,83.16,84.15,80.16,84.30,84.01,80.81,81.69,82.79,81.41,80.45,79.85,79.81,84.70,85.22,80.51,82.39,83.43,82.39,81.91,81.89,82.00,82.14,83.30,74.11)
a2 <- data.frame(Seq=seq(0, (length(First) - 1) * 3, by = 3), All=First)
a4 <- data.frame(Seq=seq(0, (length(Second) - 1) * 3, by = 3), All=Second)
sg <- rbind(a2,a4)
sg$Legend <- c(rep("First", nrow(a2)), rep("Second", nrow(a4)))
ggplot(data=sg, aes(x=Seq, y=All, col=Legend)) + geom_line()
提前致谢。
答案 0 :(得分:2)
一般来说,你现在正在做的事情是好的。以长格式获取数据并将变量映射到颜色。请参阅此处了解获得(大致)相同情节的三种方法。
library(ggplot2)
First <- c(71.54,76.48,77.58,63.80,66.16,73.22,70.71,72.94,73.22,69.37,70.49,72.25,70.94,71.54,71.01,68.36,70.46,69.22,75.98,73.66,72.90,75.74,73.55,79.48,76.37,64.62,65.86,70.08,73.40,79.72,57.43)
Second <- c(80.61,79.03,80.35,77.52,79.16,80.80,80.49,82.00,83.16,84.15,80.16,84.30,84.01,80.81,81.69,82.79,81.41,80.45,79.85,79.81,84.70,85.22,80.51,82.39,83.43,82.39,81.91,81.89,82.00,82.14,83.30,74.11)
dat1a <- data.frame(Seq=seq(0, (length(First) - 1) * 3, by = 3),
All=First)
dat1b <- data.frame(Seq=seq(0, (length(Second) - 1) * 3, by = 3),
All=Second)
dat1 <- dplyr::bind_rows(dat1a, dat1b, .id = 'Legend')
ggplot(data=dat1, aes(x=Seq, y=All, col=Legend)) + geom_line()
dat2 <- data.frame(Seq=seq(0, (max(length(First), length(Second)) - 1) * 3, by = 3),
First = c(First, NA),
Second = Second)
dat2 <- tidyr::gather(dat2, 'Legend', 'All', -Seq)
ggplot(data=dat2, aes(x=Seq, y=All, col=Legend)) + geom_line()
ggplot(mapping = aes(x=Seq, y=All)) +
geom_line(data = dat1a, aes(col = 'First')) +
geom_line(data = dat1b, aes(col = 'Second'))